Sql Alchemy有什么问题?

kn3*_*n3l 12 python mysql sqlalchemy

我得到了教程

http://www.rmunn.com/sqlalchemy-tutorial/tutorial.html

当我编译得到错误消息

The debugged program raised the exception unhandled NameError
"name 'BoundMetaData' is not defined"
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我使用的是最新的sqlAlchemy.

我怎么能修好这个?

阅读本文后,我修改了自己的最新版本sqlAlchemy:

from sqlalchemy import *
engine = create_engine('mysql://root:mypassword@localhost/mysql')
metadata = MetaData()
users = Table('users', metadata,
    Column('user_id', Integer, primary_key=True),
    Column('name', String(40)),
    Column('age', Integer),
    Column('password', String),
)
metadata.create_all(engine) 
i = users.insert()
i.execute(name='Mary', age=30, password='secret')
i.execute({'name': 'John', 'age': 42},
          {'name': 'Susan', 'age': 57},
          {'name': 'Carl', 'age': 33})
s = users.select()
rs = s.execute()
row = rs.fetchone()
print 'Id:', row[0]
print 'Name:', row['name']
print 'Age:', row.age
print 'Password:', row[users.c.password]
for row in rs:
    print row.name, 'is', row.age, 'years old
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它会引发错误

 raise exc.DBAPIError.instance(statement, parameters, e, connection_invalidated=is_disconnect)
sqlalchemy.exc.ProgrammingError: (ProgrammingError) (1064, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' \n\tPRIMARY KEY (user_id)\n)' at line 5") '\nCREATE TABLE users (\n\tuser_id INTEGER NOT NULL AUTO_INCREMENT, \n\tname VARCHAR(40), \n\tage INTEGER, \n\tpassword VARCHAR, \n\tPRIMARY KEY (user_id)\n)\n\n' ()
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sha*_*ovo 24

本教程的修复方法是使用MetaData而不是 BoundMetaData.不推荐使用BoundMetaData并将其替换为MetaData.

而在将来避免这样得到错误,请尝试官方的一个替代,如Nosklo说.

from sqlalchemy import *

db = create_engine('sqlite:///tutorial.db')

db.echo = False  # Try changing this to True and see what happens

metadata = MetaData(db)

"""
  Continue with the rest of your Python code
"""
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nos*_*klo 18

本教程适用于SQLAlchemy版本0.2.由于实际版本是0.5.7,我会说教程严重过时.

试试官方的.


编辑:

现在你有一个完全不同的问题.你应该问另一个问题而不是编辑这个问题.

你现在的问题是

Column('password', String),
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不指定列的大小.

尝试

Column('password', String(20)),
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代替.

  • 那个"官方"链接被打破了 (2认同)