我可以用逗号将多行划分为一列吗？

Question

我试图在我的SQL Server数据库中合并这样的东西:

[TicketID], [Person]
 T0001       Alice
 T0001       Bob
 T0002       Catherine
 T0002       Doug
 T0003       Elaine

进入:

[TicketID], [People]
 T0001       Alice, Bob
 T0002       Catherine, Doug
 T0003       Elaine

我需要在SQL Server和Oracle中执行此操作.

我发现GROUP_CONCATMySQL 的功能完全符合我的需要,但MySQL不是一个选项.

编辑:测试台:

DECLARE @Tickets TABLE (
    [TicketID] char(5) NOT NULL,
    [Person] nvarchar(15) NOT NULL
)

INSERT INTO @Tickets VALUES
    ('T0001', 'Alice'),
    ('T0001', 'Bob'),
    ('T0002', 'Catherine'),
    ('T0002', 'Doug'),
    ('T0003', 'Elaine')

SELECT * FROM @Tickets

Answer 1

这是一个适用于SQL Server 2005+的解决方案:

SELECT t.TicketID,
       STUFF(ISNULL((SELECT ', ' + x.Person
                FROM @Tickets x
               WHERE x.TicketID = t.TicketID
            GROUP BY x.Person
             FOR XML PATH (''), TYPE).value('.','VARCHAR(max)'), ''), 1, 2, '') [No Preceeding Comma],
       ISNULL((SELECT ', ' + x.Person
                FROM @Tickets x
               WHERE x.TicketID = t.TicketID
            GROUP BY x.Person
             FOR XML PATH (''), TYPE).value('.','VARCHAR(max)'), '') [Preceeding Comma If Not Empty]
  FROM @Tickets t
GROUP BY t.TicketID

参考:

• STUFF(Transact-SQL)

Answer 2

而且,MySQL版本,为了完整性:

select
    TicketId,
    GROUP_CONCAT(Person ORDER BY Person SEPARATOR ', ') People
from
    table
group by
    TicketId

Answer 3

DECLARE @Tickets TABLE (
    [TicketID] char(5) NOT NULL,
    [Person] nvarchar(15) NOT NULL
)
INSERT INTO @Tickets VALUES
    ('T0001', 'Alice'),
    ('T0001', 'Bob'),
    ('T0002', 'Catherine'),
    ('T0002', 'Doug'),
    ('T0003', 'Elaine')

SELECT * FROM @Tickets

Select [TicketID],
STUFF((SELECT ',' + Person FROM @Tickets WHERE (
TicketID=Result.TicketID) FOR XML PATH ('')),1,1,'') AS BATCHNOLIST
From @Tickets AS Result
GROUP BY TicketID

Answer 4

我已经找到了在Oracle中执行此操作的方法,但我仍然需要在SQL Server中执行此操作.

从http://technology.amis.nl/blog/6118/oracle-rdbms-11gr2-listagg-new-aggregation-operator-for-creating-comma-delimited-strings (感谢tanging)(ORACLE 11及以上)

select
    TicketId,
    listagg(Person, ', ') People
from
    table
group by
    TicketId

来自:http://halisway.blogspot.com/2006/08/oracle-groupconcat-updated-again.html

with
    data
as
  (
    select
        TicketId,
        Person,
        ROW_NUMBER() over (partition by TicketId order by Person) "rownum",
        COUNT(*) over (partition by TicketId) "count"
    from
        Table
  )
select
    TicketId,
    LTRIM(sys_connect_by_path(Person,','),',') People
from
    data
where
    "rownum" = "count"
start with
    "rownum" = 1
connect by
    prior TicketId = TicketId
  and
    prior "rownum" = "rownum" - 1
order by
    TicketId

Answer 5

一个例子

SELECT DISTINCT
    t.TicketID,
    STUFF((SELECT ', ', i.Person as [text()]
           FROM @Tickets i 
           WHERE i.TicketID = t.TicketID
           FOR XML PATH ('')), 1, 2, '') as People
FROM
    @Tickets t

.........或尝试..............

SELECT DISTINCT
    t.TicketID,
    STUFF((SELECT ', ' + i.Person    /* notice this line is different */
           FROM @Tickets i 
           WHERE i.TicketID = t.TicketID
           FOR XML PATH ('')), 1, 2, '') as People
FROM
    @Tickets t

/*当我将这个用于我的桌子时,这是有效的,并且信用给了我的经理ROCKS!*/