Raz*_*ick 0 c# hash switch-statement
我一直试图在C#(aaaa,aaab,aaac,... abcd,abce)中依次为哈希破解者生成密码(用于白帽).但是,我不知道该怎么做.
现在我有一个char数组,其最后一个元素由一个开关递增:
switch (character) {
case ('0'):
character = '1';
break;
case ('1'):
character = '2';
break;
case ('2'):
character = '3';
break;
case ('3'):
character = '4';
break;
case ('4'):
character = '5';
break;
case ('5'):
character = '6';
break;
case ('6'):
character = '7';
break;
case ('7'):
character = '8';
break;
case ('8'):
character = '9';
break;
case ('9'):
character = 'a';
break;
case ('a'):
character = 'b';
break;
case ('b'):
character = 'c';
break;
case ('c'):
character = 'd';
break;
case ('d'):
character = 'e';
break;
case ('e'):
character = 'f';
break;
case ('f'):
character = 'g';
break;
case ('g'):
character = 'h';
break;
case ('h'):
character = 'i';
break;
case ('i'):
character = 'j';
break;
case ('j'):
character = 'k';
break;
case ('k'):
character = 'l';
break;
case ('l'):
character = 'm';
break;
case ('m'):
character = 'n';
break;
case ('n'):
character = 'o';
break;
case ('o'):
character = 'p';
break;
case ('p'):
character = 'q';
break;
case ('q'):
character = 'r';
break;
case ('r'):
character = 's';
break;
case ('s'):
character = 't';
break;
case ('t'):
character = 'u';
break;
case ('u'):
character = 'v';
break;
case ('v'):
character = 'w';
break;
case ('w'):
character = 'x';
break;
case ('x'):
character = 'y';
break;
case ('y'):
character = 'z';
break;
case ('z'):
character = 'A';
break;
case ('A'):
character = 'B';
break;
case ('B'):
character = 'C';
break;
case ('C'):
character = 'D';
break;
case ('D'):
character = 'E';
break;
case ('E'):
character = 'F';
break;
case ('F'):
character = 'G';
break;
case ('G'):
character = 'H';
break;
case ('H'):
character = 'I';
break;
case ('I'):
character = 'J';
break;
case ('J'):
character = 'K';
break;
case ('K'):
character = 'L';
break;
case ('L'):
character = 'M';
break;
case ('M'):
character = 'N';
break;
case ('N'):
character = 'O';
break;
case ('O'):
character = 'P';
break;
case ('P'):
character = 'Q';
break;
case ('Q'):
character = 'R';
break;
case ('R'):
character = 'S';
break;
case ('S'):
character = 'T';
break;
case ('T'):
character = 'U';
break;
case ('U'):
character = 'V';
break;
case ('V'):
character = 'W';
break;
case ('W'):
character = 'X';
break;
case ('X'):
character = 'Y';
break;
case ('Y'):
character = 'Z';
break;
case ('Z'):
character = '@';
break;
case ('@'):
character = '%';
break;
case ('%'):
character = '/';
break;
case ('/'):
character = '\\';
break;
case ('\\'):
character = '\'';
break;
case ('\''):
character = '!';
break;
case ('!'):
character = '$';
break;
case ('$'):
character = '#';
break;
case ('#'):
character = '^';
break;
case ('^'):
character = '?';
break;
case ('?'):
character = ':';
break;
case (':'):
character = ',';
break;
case (','):
character = '(';
break;
case ('('):
character = ')';
break;
case (')'):
character = '[';
break;
case ('['):
character = ']';
break;
case (']'):
character = '{';
break;
case ('{'):
character = '}';
break;
case ('}'):
character = '-';
break;
case ('-'):
character = '_';
break;
case ('_'):
character = '+';
break;
case ('+'):
character = '=';
break;
case ('='):
character = '0';
break;
prev = true;
default:
character = '0';
break;
}
但是,当该元素再次达到0时,我需要增加密码的前一个数字,如果该数字也达到0,我需要增加该数字的前一个数字,依此类推.
此外,由于这是一个哈希破解者,它需要很快.有什么建议？
我的第一个答案不会给你你想要的东西.这将:
创建一个定义字母表的字符串:
const string Alphabet = "abcdefghijklmnopqrstuvwxyz0123456789";
然后用所有-1初始化一个int数组,只要你的密码最长.这个最多可以包含8个字符:
int[] pwArray = new int[] {-1, -1, -1, -1, -1, -1, -1, -1};
然后运行一个循环:
for (int i = 0; i < Whatever; ++i)
{
string password = ToPasswordString(pwArray, Alphabet);
// do something with the password
}
string ToPasswordString(int[] pass, string alphabet)
{
for (int i = pass.Length-1; i > 0; --i)
{
pass[i]++;
if (pass[i] < alphabet.Length)
{
break;
}
pass[i] = 0;
}
var sb = new StringBuilder();
for (int i = 0; i < pass.Length; ++i)
{
if (pass[i] >= 0)
sb.Append(alphabet[pass[i]]);
}
return sb.ToString();
}
这里的关键是我们不修改密码字符.相反,我们将索引修改为字符数组.
当然,这不会像其他一些方法(每秒密码)那么快,但是你的程序的速度受限于你被黑客攻击的网站响应登录尝试的速度.与此相比,您生成密码所花费的时间是无关紧要的.
而不是一个复杂的,非常大的switch语句,为什么不直接映射int值char.
for (int i = 0; i < (int)Char.MaxValue; i++) {
char c = (char)i;
...
}
这样可以很容易地构建暴力密码生成器.