Arn*_*lle 6 java postgresql jpa
在PostgreSQL中,string_agg(列,分隔符)允许聚合一些字符串.我尝试将它与JPA一起使用,但它不是JPA标准函数.
注意:这不等于CriteriaBuilder#concat().
所以,我试图告诉JPA这个函数是否存在,如下所示:
public class StringAgg extends ParameterizedFunctionExpression<String> implements Serializable {
public static final String NAME = "string_agg";
@Override
public boolean isAggregation() {
return true;
}
@Override
protected boolean isStandardJpaFunction() {
return false;
}
public StringAgg(CriteriaBuilderImpl criteriaBuilder, Expression<String> expression, String separator) {
super(criteriaBuilder, String.class, NAME, expression, new LiteralExpression(criteriaBuilder, separator));
}
}
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然后 :
Expression<String> exprStr = ...
CriteriaBuilder cb = ...
cb.construct(MyClass.class,
myClass.get(MyClass_.name),
myClass.get(MyClass_.surname),
new StringAgg(cb, exprStr, "/"));
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问题,我得到一个NullPointerException!
java.lang.NullPointerException: null
at org.hibernate.internal.util.ReflectHelper.getConstructor(ReflectHelper.java:355) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.ast.tree.ConstructorNode.resolveConstructor(ConstructorNode.java:179) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.ast.tree.ConstructorNode.prepare(ConstructorNode.java:152) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.ast.HqlSqlWalker.processConstructor(HqlSqlWalker.java:1028) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:2279) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:2145) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1451) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:571) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:299) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:247) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:261) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:189) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:141) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:119) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:87) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:190) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:288) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:223) ~[hibernate-core-4.3.0.Beta3.jar:4.3.0.Beta3]
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调试器显示忽略最后Selection一个cb.construct()(new StringAgg(cb, exprStr, "/")).因此,搜索的构造函数MyClass(String,String)代替MyClass(String, String, String).
StringAgg的实现有什么问题吗?有人已经尝试在JPA中使用string_agg吗?
解决方案(感谢vzamanillo)
扩展方言:
public class PGDialect extends PostgreSQLDialect{
public PGDialect() {
super();
registerFunction("string_agg", new SQLFunctionTemplate( StandardBasicTypes.STRING, "string_agg(?1, ?2)"));
}
}
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在persistence.xml中使用它
<properties>
<property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver"/>
<property name="hibernate.dialect" value="path.to.PGDialect"/>
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然后使用CriteriaBuilder #function():
Expression<String> exprStr = ...
CriteriaBuilder cb = ...
cb.construct(MyClass.class,
myClass.get(MyClass_.name),
myClass.get(MyClass_.surname),
cb.function( "string_agg", myColPath, cb.literal("delimiter" )));
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为了简化它,我创建了一个帮助方法:
public static Expression<String> strAgg(CriteriaBuilder cb, Expression<String> expression, String delimiter) {
return cb.function( "string_agg", String.class, expression, cb.literal(delimiter));
}
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所以代码变成:
Expression<String> exprStr = ...
CriteriaBuilder cb = ...
cb.construct(MyClass.class,
myClass.get(MyClass_.name),
myClass.get(MyClass_.surname),
strAgg(cb, myColPath, "delimiter"));
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也许这有助于你,
您可以在JPA Criteria Query中调用数据库函数.
CriteriaBuilder接口具有" 功能 "方法.
<T> Expression<T> function(String name,
Class<T> type,
Expression<?>... args)
Create an expression for the execution of a database function.
Parameters:
name - function name
type - expected result type
args - function arguments
Returns:
expression
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然后,您可以尝试创建CriteriaBuilder帮助程序类以获取可在标准查询中照常使用的普通条件表达式
public abstract class CriteriaBuilderHelper {
private static final String PG_STRING_AGG = "string_agg";
/**
* @param cb the CriteriaBuilder to use
* @param toJoin the string to join
* @param delimiter the string to use
* @return Expression<String>
*/
public static Expression functionStringAgg(CriteriaBuilder cb, String toJoin, String delimiter) {
return cb.function(PG_STRING_AGG,
String.class,
cb.literal(toJoin),
cb.literal(delimiter))
);
}
}
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或者您可以使用自定义方言注册新功能
public class PGDialect extends PostgreSQLDialect{
public PGDialect() {
super();
registerFunction("string_agg", new SQLFunctionTemplate( StandardBasicTypes.STRING, "string_agg(?1, ?2)"));
}
}
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并在CriteriaBuilder中将其用作普通函数
Expression<String> functionStringAgg = cb.function( "string_agg", String.class,
cb.parameter(String.class, "toJoin" ),
cb.parameter(String.class, "delimiter"));
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毕竟不要忘记将参数值设置为您的CriteriaQuery
setParameter( "toJoin", toJoin);
setParameter( "delimiter", delimiter);
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