use*_*418 8 timestamp syslog filter logstash logstash-grok
我有点困惑.我正试图拔出syslog date (backfilling the logstash)并替换@timestamp它.我几乎尝试了一切.
这是我的过滤器
filter {
if [type] == "syslog" {
grok {
match => {
"message" => ["%{SYSLOGTIMESTAMP:DATETIME} %{WORD:SERVER} (?<BINARY>(.*?)(php\-cgi|php))\: %{DATA:PHP_ERROR_TYPE}\:\s\s(?<PHP_ERROR_DESC>(.*?)(e\s\d))""]
}
}
date {
match => { "DATETIME" => [ "MMM d HH:mm:ss", "MMM dd HH:mm:ss", "ISO8601" ] }
target => "@timestamp"
add_tag => [ "tmatch" ]
}
if !("_grokparsefailure" in [tags]) {
mutate {
replace => [ "@source_host", "%{SERVER}" ]
}
}
mutate {
remove_field => [ "SERVER" ]
}
}
}
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样本输出:
{
"message" => "Sep 10 00:00:00 xxxxxxx",
"@timestamp" => "2013-12-05T13:29:35.169Z",
"@version" => "1",
"type" => "xxxx",
"host" => "127.0.0.1:xxx",
"DATETIME" => "Sep 10 00:00:00",
"BINARY" => "xxxx",
"PHP_ERROR_TYPE" => "xxxx",
"PHP_ERROR_DESC" => "xxxxx",
"tags" => [
[0] "tmatch"
],
"@source_host" => "xxx"
}
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tmatch在标签中,所以我假设日期过滤器有效,但为什么我仍然有:
@timestamp => "2013-12-05T13:29:35.169Z"
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?
谢谢你的帮助(我的logstash是logstash-1.2.2-flatjar.jar)
rut*_*ter 10
我们来看看你的日期过滤器:
date {
match => { "DATETIME" => [ "MMM d HH:mm:ss", "MMM dd HH:mm:ss", "ISO8601" ] }
target => "@timestamp"
add_tag => [ "tmatch" ]
}
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特别是匹配参数:
match => { "DATETIME" => [ "MMM d HH:mm:ss", "MMM dd HH:mm:ss", "ISO8601" ] }
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匹配期望一个数组.我不确定你传递的是什么,但它肯定不是一个阵列.我尝试使用它-v,我很惊讶地看到它没有抱怨.
你可能意味着更接近这个:
match => ["DATETIME", "MMM d HH:mm:ss", "MMM dd HH:mm:ss", "ISO8601"]
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注意,数组的第一个元素是目标字段; 其他元素是要匹配的模式.
过去,你真的只需要传递你期望的一种格式,但看起来它包含在你发送的三种格式中.
如果您希望时间戳显示为您的时区格式,而不是UTC时间,您可以这样做
ruby {
code => "event['@timestamp'] = event['@timestamp'].local('-08:00')"
}
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之前:@timestamp => "2013-12-05T13:29:35.169Z"
之后:@timestamp => "2013-12-05T05:29:35.169-08:00"
更新:本地方法无法在1.4.2版中运行.所以,改变另一个API
ruby {
code => "event['@timestamp'] = event['@timestamp'].getlocal"
}
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