Dee*_*ena 3 mysql inner-join subquery
我似乎在内连接中有一个子查询有问题,但是我没有.
有一个m:n表构造,有3个表,其中只有2个与问题相关.
当我像这样创建一个完整的内部联接:
SELECT count( * ) AS Count, lastname, firstname
FROM DVDPROFILER_dvd_common_actor
INNER JOIN DVDPROFILER_dvd_actor ON DVDPROFILER_dvd_common_actor.caid = DVDPROFILER_dvd_actor.caid
WHERE DVDPROFILER_dvd_actor.caid > 0
GROUP BY DVDPROFILER_dvd_actor.caid
ORDER BY Count DESC
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我得到的正是我所期待的:顶级演员按照他在任何电影中记入的时间计算,即使多次担任多个角色也是如此.
我的目标是提取有关演员被分析的电影的数量的信息,我认为 - 我很天真 - 它应该像这样简单:
SELECT count( * ) AS Count, lastname, firstname
FROM DVDPROFILER_dvd_common_actor
INNER JOIN
(SELECT caid
FROM DVDPROFILER_dvd_actor
GROUP BY id) AS DVDPROFILER_dvd_actor
ON DVDPROFILER_dvd_common_actor.caid = DVDPROFILER_dvd_actor.caid
WHERE DVDPROFILER_dvd_actor.caid > 0
GROUP BY DVDPROFILER_dvd_actor.caid
ORDER BY Count DESC
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但结果完全不正确
所以我用一个选定的actor检查了子查询
SELECT caid, id
FROM DVDPROFILER_dvd_actor
WHERE caid = 30801
GROUP BY id
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并得到我所期望的
所以我玩了一下,当我在子查询中引入LIMIT子句时,我突然得到了不同但从未正确的回复.
SELECT count( * ) AS Count, lastname, firstname
FROM DVDPROFILER_dvd_common_actor
INNER JOIN
(SELECT caid
FROM DVDPROFILER_dvd_actor
GROUP BY id
LIMIT 0 , 50000) AS DVDPROFILER_dvd_actor
ON DVDPROFILER_dvd_common_actor.caid = DVDPROFILER_dvd_actor.caid
WHERE DVDPROFILER_dvd_actor.caid > 0
GROUP BY DVDPROFILER_dvd_actor.caid
ORDER BY Count DESC
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对于不同的LIMIT,我得到了不同的结果,但在某些时候,当我超过一定限度时,结果完全没有限制 - 但同样错误.
我在这里俯瞰什么?:-(
你能试试吗?我想COUNT(DISTINCT DVDPROFILER_dvd_actor.id)
对你有帮助.
SELECT lastname, firstname, COUNT(DISTINCT DVDPROFILER_dvd_actor.id) AS Count
FROM DVDPROFILER_dvd_common_actor
INNER JOIN DVDPROFILER_dvd_actor ON DVDPROFILER_dvd_common_actor.caid = DVDPROFILER_dvd_actor.caid
WHERE DVDPROFILER_dvd_actor.caid > 0
GROUP BY lastname, firstname
ORDER BY Count DESC
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如果没有,我们非常高兴您在http://www.sqlfiddle.com/上发布数据和架构.这使我们更容易测试
谢谢.