正如我的信息所述,我继承了当地飞镖联盟的统计学家的工作.(哇哦一季20美元)
我很乐意实施ELO评级系统.
当前数据库表有超过100,000个条目.
有3种不同的游戏.单打,双打和团队.
数据库的发起者输入的游戏如下:
Index Player1_num Player2_num Opp_Player1_num Odd_Player2_num H_team V_team Season Week W L Game_type
单打游戏输入两次.
values(1,20,null,30,null,200,300,11,2,1,0,301_singles)
和
values(2,30,null,20,null,200,300,11,2,0,1,301_singles)
这样做是为了方便个人观察.
双打游戏将具有诸如的价值
(3,20,21,30,31,200,300,11,2,1,0,501_doubles)
(4,21,20,30,31,200,300,11,2,1,0,501_doubles)
(5,30,31,20,21,200,300,11,2,0,1,501_doubles)
(6,31,30,20,21,200,300,11,2,0,1,501_doubles)
同样,它是为了更容易查询查询跨季节和不同合作伙伴的赢利和损失而构建的.
团队游戏是:
(7,null,null,null,null,200,300,11,2,1,0,team_game)
所以我在表格中添加了一个match_num列,以帮助将游戏归为1个数字.
但是,我不确定如何最好地分配数字,可以理解的是,我不想手动完成所有90k条目.
注意:早期的季节是手工修改的,并非所有的双重匹配都有4个条目(有些只有1个).有些匹配也可能出现故障(而不是索引:1,2可能是1,9).
我不知道你是否需要更多信息,我不确定如何发布更大的表格示例.
Current code:
<body>
<?php
include "inc.php";
// Select Max Match Number
$sqlMatch="select max(match_num) from stats_results";
$match =mysql_query($sqlMatch);
$m= $match ? mysql_result($match,0):mysql_error();
$matchno= $m+1; // First Match number
$game=array("'301_singles'","'cricket_singles'","'501_singles'","'301_doubles'","'cricket_doubles'");
// selects max season
$sqlSeason="select max(season_index) from stats_season";
$season =mysql_query($sqlSeason);
$smax= $season ? mysql_result($season,0):mysql_error();
# $smax=2;
// for each season up to max season
for($s=1;$s<=$smax;$s++)
{
// Selects max week within the current season
$sqlWeek="select max(week) from stats_results where season=$s ";
$Week =mysql_query($sqlWeek);
$wmax= $Week ? mysql_result($Week,0):mysql_error();
# $wmax=2;
// for each week within current season up to the max week
for ($w=1;$w<=$wmax;$w++)
{
// each singles game
foreach($game as $g)
{
###########################################################################################################
$result = mysql_query("SELECT * FROM stats_results where season=$s and week=$w and game_code=$g ;") or die(mysql_error());
// Put them in array
for($i = 0; $rows[$i] = mysql_fetch_assoc($result); $i++) ;
// Delete last empty one
array_pop($rows);
//******************************************************
$matches=array();
foreach($rows as $record)
{
// Get a unique match code for this match
$matchid= getMatchID($record);
// Have we seen this ID before? If yes add this record index to the existing array
// otherwise create an array with just this value
if (!isset($matches[$matchid])) $matches[$matchid]= array($record['index_results']); // No
else $matches[$matchid][]= $record['index_results']; // Yes, add this Index
}
// Now $matches is an array of arrays of Index values, grouped by "match" so...
/* Sort $matches by key (see getMatchID for why!) */
ksort($matches);
// Update the table
foreach($matches as $match)
{
// Create SQL instruction to set the match_num for all the Index values in each entry
$sql= "UPDATE stats_results SET match_num = $matchno WHERE index_results IN (".implode(",", $match).")";
echo "<br>";
echo $sql;
/* Execute the SQL using your chosen method! */
// Move the match count on
$matchno++;
}
// End our loops
}
}
}
function getMatchID($gamerecord)
{
$index= "{$gamerecord['season']}-{$gamerecord['week']}-{$gamerecord['game_code']}-";
$players= array(
$gamerecord['player1_num'],
empty($gamerecord['player2_num'])?0:$gamerecord['player2_num'],
$gamerecord['opp_player1_num'],
empty($gamerecord['opp_player2_num'])?0:$gamerecord['opp_player2_num']
);
// Sort the players to get them in a consistent order
sort($players);
// Add the sorted players to the index
$index.= implode('-', $players);
return $index;
}
?>
</body>
（我将其放入答案中，以便我可以使其布局更好一些 - 但这并不是真正的“解决方案”！）
我认为我要做的是尝试构建一个Index按游戏分组的值数组的数组 - 然后您可以使用它来创建 SQL 来更新表。
因此，如果$rows是所有记录的数组，我们将执行类似于以下伪代码的操作：
$matches= array();
foreach($rows as $record)
{
// Get a unique match code for this match
$matchid= getMatchID($record);
// Have we seen this ID before? If yes add this record index to the existing array
// otherwise create an array with just this value
if (!isset($matches[$matchid])) $matches[$matchid]= array($record['Index']); // No
else $matches[$matchid][]= $record['Index']; // Yes, add this Index
}
// Now $matches is an array of arrays of Index values, grouped by "match" so...
/* Sort $matches by key (see getMatchID for why!) */
ksort($matches);
// Update the table
$matchno= 1; // First Match number
foreach($matches as $match)
{
// Create SQL instruction to set the match_num for all the Index values in each entry
$sql= "UPDATE games SET match_num = $matchno WHERE Index IN (".implode(",", $match).")";
/* Execute the SQL using your chosen method! */
// Move the match count on
$matchno++;
}
所以剩下的就是getMatchID函数 - 如果我们根据每场比赛的季节、周和参与者的排序列表（并首先使用季节和周）为每场比赛提供一个临时 ID，该 ID 对于每场比赛来说应该是唯一的，我们可以按稍后使用此索引以使游戏按正确的顺序排列。再次用粗略的伪代码，类似：
function getMatchID($gamerecord)
{
$index= "{$gamerecord['Season']}-{$gamerecord['Week']}-{$gamerecord['H_Team']}-{$gamerecord['V_Team']}-";
$players= array(
empty($gamerecord['Player1_Num'])?0:$gamerecord['Player1_Num'],
empty($gamerecord['Player2_Num'])?0:$gamerecord['Player2_Num'],
empty($gamerecord['Opp_Player1_Num'])?0:$gamerecord['Opp_Player1_Num'],
empty($gamerecord['Opp_Player2_Num'])?0:$gamerecord['Opp_Player2_Num']
);
// Sort the players to get them in a consistent order
sort($players);
// Add the sorted players to the index
$index.= implode('-', $players);
return $index;
}
因此，一切顺利$index都会回来，就像11-2-200-300-0-0-20-30您的示例中的第一场单打比赛一样 - 无论我们查看的是哪场比赛记录。
这有意义/有帮助吗？