如何在没有脚本死亡的情况下使用异常？

Question

我想在我的代码的一部分中使用异常来处理错误,但如果代码失败,我希望脚本继续.我想记录错误.有人可以帮我解决这个问题吗？

---

try{
    if($id == 4)
    {
      echo'test';
    }
}
catch(Exception $e){
    echo $e->getMessage();
}

echo'Hello, you should see me...'; <------ I never see this.. No errors, just a trace.

Answer 1

你必须抓住异常:

// some code

try {
    // some code, that might throw an exception
    // Note that, when the exception is thrown, the code that's after what
    // threw it, until the end of this "try" block, will not be executed
} catch (Exception $e) {
    // deal with the exception
    // code that will be executed only when an exception is thrown
    echo $e->getMessage(); // for instance
}

// some code, that will always be executed

以下是您应该阅读的一些内容:

• PHP手册中的例外情况
• 特殊PHP:异常简介