dlg*_*ght 4 javascript jquery json google-visualization str-replace
我有这个Json字符串,我用于谷歌图表可视化,需要采用这种确切的格式,我需要将数字"v"的每个值替换为其数值(不带""的值).我应该做一些javascript替换功能,但我找不到一种方法来移动json对象.这是我应该修改的示例json字符串:
{"cols":[
{"id":"r","label":"Reason","type":"string"},
{"id":"m","label":"Minutes","type":"number"}
],
"rows":[
{"c":[
{"v":"Flour - Blower","f":"Flour - Blower"},
{"v":"7","f":"7"}]},
{"c":[
{"v":"Whole Line - d","f":"Whole Line - d"},
{"v":"4","f":"4"}]},
{"c":[
{"v":"Flour - Pipework","f":"Flour - Pipework"},
{"v":"3","f":"3"}]},
{"c":[
{"v":"Horseshoe - Belt","f":"Horseshoe - Belt"},
{"v":"1","f":"1"}]}
],
"p":null
}
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可能我应该这样做:
var jsonStr = ...;
for (i in jsonStr.rows) {
for(j in jsonStr[i].c)
{
if (parseInt(jsonStr[i].c[j].v) != 'NaN') {
jsonStr.rows[i].c[j].v = parseInt(jsonStr.rows[i].c[j].v);
}
}
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由于JSON实际上是一个字符串,为什么不将整个字符串放在全局字符串中string.replace:
jsonStr = JSON.stringify(jsonStr);
jsonStr = jsonStr.replace(/"v":"(\d+)"/g, '"v":$1');
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