jodatime期间不正确 - 年月日

Question

我使用jodatime创建了一个Utility方法来计算日期差异并显示它,例如3y 2m 4d.

这是我的方法:

public static String dateBetween(Object start, Object end) {
    Period period = new Period(new LocalDate(start), new LocalDate(end));
    PeriodFormatter formatter = new PeriodFormatterBuilder()
            .printZeroAlways()
            .appendYears().appendSuffix("y ")
            .appendMonths().appendSuffix("m ")
            .appendDays().appendSuffix("d")
            .toFormatter();
    return formatter.print(period);
}

使用testng创建测试脚本如下:

@DataProvider(name = "dateBetweenData")
public static Object[][] dateBetweenData() {
    return new Object[][] { 
            { "01/08/2010", "02/07/2012", "1y 11m 1d" },
            { "01/08/2010", "03/07/2012", "1y 11m 2d" },
            { "01/08/2010", "11/07/2012", "1y 11m 10d" },
            { "01/08/2010", "21/07/2012", "1y 11m 20d" },
            { "01/08/2010", "31/07/2012", "1y 11m 30d" },
    };
}

@Test(dataProvider="dateBetweenData")
public void dateBetween(String startDate, String endDate, String expected) throws ParseException {
    DateFormat format = new SimpleDateFormat("dd/MM/yyyy");
    Assert.assertEquals(
            DateUtil.dateBetween(format.parse(startDate), format.parse(endDate)), 
            expected);
}

我注意到我的一些测试失败了:

PASSED: dateBetween("01/08/2010", "02/07/2012", "1y 11m 1d")
PASSED: dateBetween("01/08/2010", "03/07/2012", "1y 11m 2d")
FAILED: dateBetween("01/08/2010", "11/07/2012", "1y 11m 10d")
java.lang.AssertionError: expected [1y 11m 10d] but found [1y 11m 3d]
...
FAILED: dateBetween("01/08/2010", "21/07/2012", "1y 11m 20d")
java.lang.AssertionError: expected [1y 11m 20d] but found [1y 11m 6d]
...
FAILED: dateBetween("01/08/2010", "31/07/2012", "1y 11m 30d")
java.lang.AssertionError: expected [1y 11m 30d] but found [1y 11m 2d]
...
===============================================
    Default test
    Tests run: 5, Failures: 3, Skips: 0
===============================================

我使用错误的方法还是jodatime中的错误？

注意:我正在使用jodatime 2.3和testng 6.8.7.

Answer 1

不幸的是,Joda Time中的标准句点类型包括几周(是的 - 根本不直观,因此仅仅编写新的Period(from,to)是不够的,但是使用具有显式句点类型参数的备选3-args-constructor您只能指定年,月和日的地方.

解:

Period period = 
  new Period(new LocalDate(start), new LocalDate(end), PeriodType.yearMonthDay());