mbu*_*ill 5 c# system.reactive async-await
这个人为的例子大致是我的代码的结构:
public abstract class SuperHeroBase
{
protected SuperHeroBase() { }
public async Task<CrimeFightingResult> FightCrimeAsync()
{
var result = new CrimeFightingResult();
result.State = CrimeFightingStates.Fighting;
try
{
await FightCrimeOverride(results);
}
catch
{
SetError(results);
}
if (result.State == CrimeFightingStates.Fighting)
result.State = CrimeFightingStates.GoodGuyWon;
return result;
}
protected SetError(CrimeFightingResult results)
{
result.State = CrimeFightingStates.BadGuyWon;
}
protected abstract Task FightCrimeOverride(CrimeFightingResult results);
}
public enum CrimeFightingStates
{
NotStarted,
Fighting,
GoodGuyWon, // success state
BadGuyWon // error state
}
public class CrimeFightingResult
{
internal class CrimeFightingResult() { }
public CrimeFightingStates State { get; internal set; }
}
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现在我正在尝试构建一个可以容纳多个SuperHero对象并提供AllHerosFightCrime方法的集合.英雄不应该一次全部战斗(下一个在第一个完成时开始).
public class SuperHeroCollection : ObservableCollection<SuperHeroBase>
{
public SuperHeroCollection() { }
// I mark the method async...
public async IObservable<CrimeFightingResult> AllHerosFightCrime()
{
var heros = new List<SuperHeroBase>(this);
var results = new ReplaySubject<CrimeFightingResult>();
foreach (var hero in heros)
{
// ... so I can await on FightCrimeAsync and push
// the result to the subject when done
var result = await hero.FightCrimeAsync();
results.OnNext(result);
}
results.OnCompleted();
// I can't return the IObservable here because the method is marked Async.
// It expects a return type of CrimeFightingResult
return results;
}
}
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我该如何归还IObservable<CrimeFightingResults>仍然有FightCrimeAsync等待的电话?
您可以将您的任务转变为可观察的任务,并使用以下方法将它们组合起来Merge:
public IObservable<CrimeFightingResult> AllHerosFightCrime()
{
var heros = new List<SuperHeroBase>(this);
return heros.Select(h => h.FightCrimeAsync().ToObservable())
.Merge();
}
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如果您想保持事件接收的顺序,您可以使用Concat代替Merge。
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