Pie*_*per 22
QKeyEvent *event = new QKeyEvent ( QEvent::KeyPress, Qt::Key_Enter);
QCoreApplication::postEvent (receiver, event)
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dnl*_*crl 22
正确答案可能是这样的:
QKeyEvent *event = new QKeyEvent ( QEvent::KeyPress, Qt::Key_Enter, Qt::NoModifier);
QCoreApplication::postEvent (receiver, event);
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实际上没有匹配的函数来调用
QtKeyEvent::QtKeyEvent(Type type, int key)
但是还有:
QtKeyEvent::QtKeyEvent(Type type, int key, Qt::KeyboardModifiers modifiers)