以Python形式将标头添加到csv文件中

alb*_*s_c 64 python csv header

我编写了一个合并两个csv文件的Python脚本,现在我想在最终的csv中添加一个标题.我尝试按照此处报告的建议,我收到以下错误:expected string, float found.什么是解决这个问题的最pythonic方法?

这是我正在使用的代码:

import csv

with open('combined_file.csv', 'w', newline='') as outcsv:
    writer = csv.DictWriter(outcsv, fieldnames = ["Date", "temperature 1", "Temperature 2"])
    writer.writeheader()

    with open('t1.csv', 'r', newline='') as incsv:
        reader = csv.reader(incsv)
        writer.writerows(row + [0.0] for row in reader)

    with open('t2.csv', 'r', newline='') as incsv:
        reader = csv.reader(incsv)
        writer.writerows(row[:1] + [0.0] + row[1:] for row in reader)
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Mar*_*ers 91

DictWriter()班预计字典的每一行.如果您只想写一个初始标题,请使用常规标题csv.writer()并为标题传入一个简单的行:

import csv

with open('combined_file.csv', 'w', newline='') as outcsv:
    writer = csv.writer(outcsv)
    writer.writerow(["Date", "temperature 1", "Temperature 2"])

    with open('t1.csv', 'r', newline='') as incsv:
        reader = csv.reader(incsv)
        writer.writerows(row + [0.0] for row in reader)

    with open('t2.csv', 'r', newline='') as incsv:
        reader = csv.reader(incsv)
        writer.writerows(row[:1] + [0.0] + row[1:] for row in reader)
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另一种方法是在复制数据时生成字典:

import csv

with open('combined_file.csv', 'w', newline='') as outcsv:
    writer = csv.DictWriter(outcsv, fieldnames = ["Date", "temperature 1", "Temperature 2"])
    writer.writeheader()

    with open('t1.csv', 'r', newline='') as incsv:
        reader = csv.reader(incsv)
        writer.writerows({'Date': row[0], 'temperature 1': row[1], 'temperature 2': 0.0} for row in reader)

    with open('t2.csv', 'r', newline='') as incsv:
        reader = csv.reader(incsv)
        writer.writerows({'Date': row[0], 'temperature 1': 0.0, 'temperature 2': row[1]} for row in reader)
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  • @pcarter:在Python 2上,在Windows上以文本模式打开文件会触发与CSV格式不兼容的换行符; 因此`csv`模块想直接处理换行符(根据需要使用`\n`和`\ r \n`),这意味着你必须以二进制模式打开文件.请参阅[`csv.reader()`文档](https://docs.python.org/2/library/csv.html#csv.reader):*如果csvfile是文件对象,则必须使用'b'标志在平台上有所作为.*.在Python 3上,您将使用[`newline =''`选项](https://docs.python.org/3/library/csv.html#id3). (3认同)
  • @loretoparisi:当然可以。附加到现有文件时不要使用 writer.writeheader() 。`csv.writer()` 对象无法检测到您正在将数据写入现有文件。 (2认同)

小智 8

您只需在执行循环之前添加一行。此行包含您的 CSV 文件标题名称。

schema = ['a','b','c','b']
row = 4
generators = ['A','B','C','D']
with open('test.csv','wb') as csvfile:    
     writer = csv.writer(csvfile, delimiter=delimiter)
# Gives the header name row into csv
     writer.writerow([g for g in schema])   
#Data add in csv file       
     for x in xrange(rows):
         writer.writerow([g() for g in generators])
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sag*_*gzz 6

这对我有用。

header = ['row1', 'row2', 'row3']
some_list = [1, 2, 3]
with open('test.csv', 'wt', newline ='') as file:
    writer = csv.writer(file, delimiter=',')
    writer.writerow(i for i in header)
    for j in some_list:
        writer.writerow(j)
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  • 使用文件作为变量不是一个好主意。第 3 行。使用 csvfile 或其他文件代替。 (3认同)
  • @Gorgonzola 这只是 StackOverflow 答案中的一个语法名称...可能是香蕉,但在本例中它只是一个文件 (2认同)