RSA加密/解密在我自己的python实现中失败

Question

我正在为学校做一项工作,我必须实现rsa生成公钥/私钥和加密/解密二进制消息.我已经生成了公钥/私钥,但我的加密/解密功能不起作用.我没有得到任何执行错误,但是当我解密时,我加密的消息不一样.

我加密块的代码:

def encrypt_block(block,block_size,e,n):
    number = int(block,2) #convert to decimal number
    cipher_number = pow(number,e,n) #method for fastest exponentiation number^e mod n
    cipher_size = len(bin(cipher_number)) - 2
    tmp_text = '{0:b}'.format(cipher_number) 
    while(len(tmp_text)<block_size): #add zeros to left to fill until block_size
        tmp_text = "0" + tmp_text
    return tmp_text

我的加密代码:

    block_size = len(bin(n-1)) - 2 #size of encrypted blocks
    text_size = block_size - 5 #size of clear text blocks

    tmp_text = "" #variable for holding current block
    encrypted_message = ""

    for i in data:
        if(len(tmp_text)==text_size): #when a block is complete
            tmp_text = encrypt_block('1'+tmp_text,block_size,e,n) #add '1' so I don t loose left zeros
            encrypted_message += tmp_text
            tmp_text = ""
        if(i == '0' or i == '1'): #just precaution so I won t add other characters
            tmp_text += i


    if(tmp_text != ""): # in case last block isnt the clear text size
        tmp_text = encrypt_block('1'+tmp_text,block_size,e,n) #add '1' so I don t loose left zeros
            encrypted_message += tmp_text

    print encrypted_message

我的解密方法:

    block_size = len(bin(n-1)) - 2

    tmp_text = ""
    decrypted_message = ""

    for i in data:
        if(len(tmp_text) == block_size): 
            number = int(tmp_text,2) 
            plain_number = pow(number,d,n) 
            decrypted_message += '{0:b}'.format(plain_number)[1::] #remove the '1' that I added in all blocks to prevent loosing zeros
        if(i == '1' or i == '0'):
            tmp_text += i

    print decrypted_message

例如,如果我的消息是:

11001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011110011001111001100111100110011

我收到此加密消息(密钥大小为64位或更多位):

0101110010110010100110111010111011111001001101010110010100000110011011101111101111100000011110101101010000000001010110000111010101001000111100000011110110110011111001111000111000101011000000101111000100110100100100010100000000011101111110111101100011110011010001111000000101010010100111010010001000110010100111111000101001010101100010101001010000110010001101000111001111110010110111001000100101001000100100110011010101000111100101100111010110010000101111100111001001100110111110000100100001010100100110110100100011100010010100101000111011101101111110001000010111101111110000100001011100110010101111010010001011101000111100110101110111011100100001000010100011010001010111010000011100111100001110100100011100000101011011000001010001011101011111010110111001111001011001100001010010110000

当我解密时,我得到这个:

0000110010111101000001100010110000010000110110111110001010110011100010111010111001100011110101100

有谁知道为什么这不起作用？

Answer 1

我已经发现了错误。我的黄金一代遇到了问题。但在这段代码中我还是遇到了问题。

在加密中，我验证循环完成后是否有一些块需要加密。但在解密过程中，我没有进行验证，并且我的最后一个块从未被解密。我可以把

if(i == '1' or i == '0'):
    tmp_text += i

在我的 for 或 的开头，我会在最后放一个 if ，这样我就不会丢失最后一个块。