正则表达式匹配4组中的2组

Eug*_* S. 5 javascript c# regex asp.net-mvc

我希望单个Regex表达式匹配2组小写,大写,数字或特殊字符.长度也需要大于7.

我目前有这个表达方式

^(?=.*[^a-zA-Z])(?=.*[a-z])(?=.*[A-Z]).{8,}$
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但是,它强制字符串具有小写和大写以及数字或特殊字符.

我目前使用4个不同的正则表达式实现了这个,我用一些C#代码询问.

我计划在JavaScript中重用相同的表达式.

这是示例控制台应用程序,显示了两种方法之间的差异.

class Program
{
    private static readonly Regex[] Regexs = new[] {
        new Regex("[a-z]", RegexOptions.Compiled), //Lowercase Letter
        new Regex("[A-Z]", RegexOptions.Compiled), // Uppercase Letter
        new Regex(@"\d", RegexOptions.Compiled), // Numeric
        new Regex(@"[^a-zA-Z\d\s:]", RegexOptions.Compiled) // Non AlphaNumeric
    };

    static void Main(string[] args)
    {
        Regex expression = new Regex(@"^(?=.*[^a-zA-Z])(?=.*[a-z])(?=.*[A-Z]).{8,}$", RegexOptions.ECMAScript & RegexOptions.Compiled);

        string[] testCases = new[] { "P@ssword", "Password", "P2ssword", "xpo123", "xpo123!", "xpo123!123@@", "Myxpo123!123@@", "Something_Really_Complex123!#43@2*333" };

        Console.WriteLine("{0}\t{1}\t", "Single", "C# Hack");
        Console.WriteLine("");
        foreach (var testCase in testCases)
        {
            Console.WriteLine("{0}\t{2}\t : {1}", expression.IsMatch(testCase), testCase, 
                    (testCase.Length >= 8 && Regexs.Count(x => x.IsMatch(testCase)) >= 2));
        }

        Console.ReadKey();
    }
}

Result  Proper     Test String
------- -------    ------------

True    True     : P@ssword
False   True     : Password
True    True     : P2ssword
False   False    : xpo123
False   False    : xpo123!
False   True     : xpo123!123@@
True    True     : Myxpo123!123@@
True    True     : Something_Really_Complex123!#43@2*333
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Cas*_*yte 2

对于 javascript,您可以使用此模式来查找不同字符类之间的边界:

^(?=.*(?:.\b.|(?i)(?:[a-z]\d|\d[a-z])|[a-z][A-Z]|[A-Z][a-z]))[^:\s]{8,}$
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如果找到边界,你肯定有两个不同的类。

图案细节:

\b # is a zero width assertion, it's a boundary between a member of 
   # the \w class and an other character that is not from this class.

.\b. # represents the two characters with the word boundary.
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字母和数字之间的边界:

(?i) # make the subpattern case insensitive
(?:
    [a-z]\d # a letter and a digit
  |         # OR
    \d[a-z] # a digit and a letter
)
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大写字母和小写字母之间的边界:

[a-z][A-Z] | [A-Z][a-z]
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由于所有交替都至少包含来自两个不同字符类的两个字符,因此您一定会获得您希望的结果。