3ya*_*uya 1 parallel-processing concurrency erlang functional-programming list
我目前的目标是编写计算N个元素列表的Erlang代码,其中每个元素都是它的"索引"的因子(因此,对于N = 10,我想得到[1!,2!,3!, ......,10!]).更重要的是,我希望每个元素都能在一个单独的过程中计算出来(我知道它只是效率低下,但我希望能够实现它并将其效率与其他方法进行比较).
在我的代码中,我想使用一个函数作为给定N的"循环",对于N,N-1,N-2 ...产生一个计算阶乘(N)并将结果发送到某些"收集"的过程"函数,将收到的结果打包到列表中.我知道我的概念可能过于复杂,所以希望代码可以解释一下:
messageFactorial(N, listPID) ->
listPID ! factorial(N). %% send calculated factorial to "collector".
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
nProcessesFactorialList(-1) ->
ok;
nProcessesFactorialList(N) ->
spawn(pFactorial, messageFactorial, [N, listPID]), %%for each N spawn...
nProcessesFactorialList(N-1).
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
listPrepare(List) -> %% "collector", for the last factorial returns
receive %% a list of factorials (1! = 1).
1 -> List;
X ->
listPrepare([X | List])
end.
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
startProcessesFactorialList(N) ->
register(listPID, spawn(pFactorial, listPrepare, [[]])),
nProcessesFactorialList(N).
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我想它会起作用,我的意思是listPrepare最终会返回一个阶乘列表.但问题是,我不知道如何获得该列表,如何获得它返回的内容?至于现在我的代码返回ok,因为这是nProcessesFactorialList在完成时返回的内容.我想到最后将listPrepare的结果列表发送到nProcessesFactorialList,但是它还需要是一个注册过程,我不知道如何恢复该列表.
基本上,如何从注册过程运行listPrepare(这是我的阶乘列表)中得到结果?如果我的代码根本不对,我会问一个如何让它变得更好的建议.提前致谢.
我的方法是如何完成这类任务
-module(par_fact).
-export([calc/1]).
fact(X) -> fact(X, 1).
fact(0, R) -> R;
fact(X, R) when X > 0 -> fact(X-1, R*X).
calc(N) ->
Self = self(),
Pids = [ spawn_link(fun() -> Self ! {self(), {X, fact(X)}} end)
|| X <- lists:seq(1, N) ],
[ receive {Pid, R} -> R end || Pid <- Pids ].
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结果:
> par_fact:calc(25).
[{1,1},
{2,2},
{3,6},
{4,24},
{5,120},
{6,720},
{7,5040},
{8,40320},
{9,362880},
{10,3628800},
{11,39916800},
{12,479001600},
{13,6227020800},
{14,87178291200},
{15,1307674368000},
{16,20922789888000},
{17,355687428096000},
{18,6402373705728000},
{19,121645100408832000},
{20,2432902008176640000},
{21,51090942171709440000},
{22,1124000727777607680000},
{23,25852016738884976640000},
{24,620448401733239439360000},
{25,15511210043330985984000000}]
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