python 2.7 字符 \u2013

Question

我有以下代码：

# -*- coding: utf-8 -*-

print u"William Burges (1827–81) was an English architect and designer."

当我尝试从 cmd 运行它时。我收到以下消息：

Traceback (most recent call last):
  File "C:\Python27\utf8.py", line 3, in <module>
    print u"William Burges (1827???81) was an English architect and designer."
  File "C:\Python27\lib\encodings\cp775.py", line 12, in encode
    return codecs.charmap_encode(input,errors,encoding_map)
UnicodeEncodeError: 'charmap' codec can't encode character u'\u2013' in position
 20: character maps to <undefined>

我怎样才能解决这个问题并使 Python 读取这个 \u2013 字符？以及为什么 Python 不使用现有代码读取它，我认为 utf-8 适用于每个字符。

谢谢

编辑：

此代码打印出想要的结果：

# -*- coding: utf-8 -*-

print unicode("William Burges (1827-81) was an English architect and designer.", "utf-8").encode("cp866")

但是当我尝试打印多个句子时，例如：

# -*- coding: utf-8 -*-

print unicode("William Burges (1827–81) was an English architect and designer. I am here. ", "utf-8").encode("cp866")

我收到相同的错误消息：

Traceback (most recent call last):
  File "C:\Python27\utf8vs.py", line 3, in <module>
    print unicode("William Burges (1827???81) was an English architect and desig
ner. I am here. ", "utf-8").encode("cp866")
  File "C:\Python27\lib\encodings\cp866.py", line 12, in encode
    return codecs.charmap_encode(input,errors,encoding_map)
UnicodeEncodeError: 'charmap' codec can't encode character u'\u2013' in position
 20: character maps to <undefined>

Answer 1

我怀疑问题出在 print 语句上，而不是 python 固有的任何东西（它在我的 Mac 上工作正常）。为了打印字符串，需要将其转换为可显示的格式；您使用的较长破折号在 Windows 命令行的默认字符集中无法显示。

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你的两个句子之间的区别不在于长度，而在于“(1827-81)”与“(1827\xe2\x80\x9381)”中使用的破折号的种类 - 你能看到细微的差别吗？尝试将一个复制并粘贴到另一个上以进行检查。

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另请参阅Python、Unicode 和 Windows 控制台。

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