打开网址与本地通知ios

Question

我一直在寻找答案,但我似乎找不到答案.我想要做的是让我的应用程序在后台运行应用程序时发送本地通知,当用户打开通知时,它会将他们带到网站.我已经完成了所有设置,但它一直打开应用程序,而不是去网站.

我的问题是,这甚至可能吗？如果是这样,请问下面我的代码出错了？谢谢您的帮助.

码:

- (void)applicationDidEnterBackground:(UIApplication*)application {//使用此方法释放共享资源,保存用户数据,使计时器无效,并存储足够的应用程序状态信息,以便将应用程序恢复到当前状态,以防以后终止.//如果您的应用程序支持后台执行,则在用户退出时调用此方法而不是applicationWillTerminate:

    NSDate *date = [NSDate date];
    NSDate *futureDate = [date dateByAddingTimeInterval:3];
    notifyAlarm.fireDate = futureDate;
    notifyAlarm.timeZone = [NSTimeZone defaultTimeZone];
    notifyAlarm.repeatInterval = 0;
    notifyAlarm.alertBody = @"Visit Our Website for more info";
    [app scheduleLocalNotification:notifyAlarm];

    if ( [notifyAlarm.alertBody isEqualToString:@"Visit Our Website for more info"] ) {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.bluemoonstudios.com.au"]];
    }

Answer 1

在您的业务逻辑中

-(void)scheduleNotificationForDate:(NSDate *)fireDate{
    UILocalNotification *notification = [[UILocalNotification alloc] init];

    notification.fireDate = fireDate;
    notification.alertAction = @"View";
    notification.alertBody = @"New Message Received";
    notification.userInfo = @{@"SiteURLKey": @"http://www.google.com"};
    [[UIApplication sharedApplication] scheduleLocalNotification:notification];

}

在你的AppDelegate中

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
    UILocalNotification *notification = [launchOptions objectForKey:UIApplicationLaunchOptionsLocalNotificationKey];

    if(notification != nil){
        NSDictionary *userInfo = notification.userInfo;
        NSURL *siteURL = [NSURL URLWithString:[userInfo objectForKey:@"SiteURLKey"]];

        [[UIApplication sharedApplication] openURL:siteURL];
    }
}


-(void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification{

    NSDictionary *userInfo = notification.userInfo;
    NSURL *siteURL = [NSURL URLWithString:[userInfo objectForKey:@"SiteURLKey"]];
    [[UIApplication sharedApplication] openURL:siteURL];
}