代码阻止问题

Question

嗨,我正在做一个课程作业,我很难收到我得到的错误信息,他们是:

error 'strtoul' was not declared in this scope
error 'print' was not declared in this scope
error 'printf' was not declared in this scope

我输入的代码是:

using namespace std;

int main (int argc, const char * argv[]) {

unsigned long int a, tmp;

a = strtoul("01011111000110001001001011010011",ULL,2);
print(a);

//We always work on "a" pattern
print(tmp = a >> 4);
print(tmp = a << 6);
print(tmp = a & (long int) 0x3);
print(tmp = a & (char) 0x3);
print(tmp = a | (unsigned short) 0xf00f);
print(tmp = a ^ (long int) 0xf0f0f0f0);

return 0;
}


//Function prints unsigned long integer in hexadecimal and binary notation
void print(unsigned long b)


{

    int i, no_bits = 8 * sizeof(unsigned long);
    char binary[no_bits];

    //Print hexadecimal notation
    printf("Hex: %X\n", b);

    //Set up all 32 bits with 0
    for (i = 0; i < no_bits; i++) binary[i] = 0;

    //Count and save binary value
    for (i = 0; b != 0; i++) {
        binary[i] = b % 2;
        b = b/2;
    }

    //Print binary notation
    printf("Bin: ");
    for (i = 0 ; i < no_bits; i++) {
        if ((i % 4 == 0) && (i > 0)) printf(" ");
        printf("%d", binary[(no_bits - 1) - i]);
    }
    printf("\n\n");
}

但我一直得到错误消息:

error 'strtoul' was not declared in this scope
error 'print' was not declared in this scope
error 'printf' was not declared in this scope

无论我尝试什么,当我尝试并声明它们时,我一直得到相同的错误消息,那里有任何帮助？

非常感激,

本

Answer 1

您需要在程序顶部包含这些头文件:

#include <stdlib.h>
#include <stdio.h>

该标准输入输出库让你做输入/输出操作和STDLIB库定义了几个通用的功能,包括将字符串转换为无符号长整型.

您将要移动你的print方法之前main,你也应该改变ULL,以NULL当你打电话strtoul,因为我相信这是一个错字.您可以在我提供的链接中查看文档.