mar*_*rwy 4 python django django-rest-framework
我有以下型号:
class Song(models.Model):
name = models.CharField(max_length=64)
def __unicode__(self):
return self.name
class UserProfile(AbstractUser):
current = models.ManyToManyField(Song, related_name="in_current", blank=True)
saved = models.ManyToManyField(Song, related_name="in_saved", blank=True)
whatever = models.ManyToManyField(Song, related_name="in_whatever", blank=True)
def __unicode__(self):
return self.get_username()
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以及序列化器:
class SongSerializer(serializers.ModelSerializer):
class Meta:
model = Song
class UserProfileSongsSerializer(serializers.ModelSerializer):
current = SongSerializer(many=True)
saved = SongSerializer(many=True)
whatever = SongSerializer(many=True)
class Meta:
model = UserProfile
fields = ("id", "current", "saved", "whatever")
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并且我正在使用UpdateAPIView:
class UserProfileSongsUpdate(generics.UpdateAPIView):
queryset = UserProfile.objects.all()
serializer_class = UserProfileSongsSerializer
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问题:我无法将歌曲(即使它已经存在于数据库中)添加到任何(当前,已保存,无论如何),我只能删除它.
curl -X PUT -d '{"current": [{"id": 1, "name": "sialalalal"}, {"id": 2, "name": "imissmykitty"}], "saved": [{"id": 3, "name": "kittyontheroad"}], "whatever": []}' -H "Content-Type:application/json" localhost:8000/userprofile/1/songs/update/
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这将删除当前集合中的所有其他歌曲(这很好:)),但是当我尝试将现有歌曲添加到当前集合时,它将显示错误:
curl -X PUT -d '{"current": [{"id": 1, "name": "sialalalal"}, {"id": 2, "name": "imissmykitty"}, {"id": 7, "name": "vivalakita"}], "saved": [{"id": 3, "name": "kittyontheroad"}], "whatever": []}' -H "Content-Type:application/json" localhost:8000/userprofile/1/songs/update/
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我明白了:
{"current": [{}, {}, {"non_field_errors": ["Cannot create a new item, only existing items may be updated."]}]}
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但!如果我删除序列化字段:
class UserProfileSongsSerializer(serializers.ModelSerializer):
class Meta:
model = UserProfile
fields = ("id", "current", "saved", "whatever")
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我这样做:
curl -X PUT -d '{"current": [1, 2, 7], "saved": [3], "whatever": []}' -H "Content-Type:application/json" localhost:8000/userprofile/1/songs/update/
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它添加了没有任何问题的歌曲......
我可以添加和删除当前集合中的歌曲,并使用序列化程序作为字段保存吗?
是的你可以.你需要设置allow_add_remove到True和read_only到False:
current = SongSerializer(many=True, allow_add_remove=True, read_only=False)
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请注意,嵌套序列化程序的当前实现将从DB中删除整个Song对象,而不仅仅是关系.
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