sta*_*ser 1 sql t-sql sql-server
我有一张桌子如下图所示.
ID ParentID Node Name Node Type
------------------------------------------------------------------
525 524 Root Area Level 1
526 525 C Area Level 2
527 525 A Area Level 2
528 525 D Area Level 2
671 525 E Area Level 2
660 527 B Area Level 3
672 671 F Area Level 3
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如何编写递归t-sql查询以生成以下输出?
输出(输出中不需要"Root"节点):
Node ID
-----------------------
A 527
A/B 660
C 526
D 528
E 671
E/F 672
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谢谢
使用公用表表达式查看此页面.这就是我要使用的(假设您至少使用SQL Server 2005)
以下是使用您的案例的代码示例:
WITH CTE (NodePath, ID) AS (
SELECT
'/' + CAST(NodeName AS NVARCHAR(MAX)) AS NodePath,
ID
FROM TABLE
WHERE NodeName = 'Root'
UNION ALL
SELECT
CTE.NodePath + '/' + CAST(NodeName AS NVARCHAR(MAX)) AS NodePath,
TABLE.ID
FROM CTE
INNER JOIN TABLE ON TABLE.ParentId = CTE.ID
)
SELECT
NodeName,
ID
FROM CTE
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