用Java解析JSON数据

Question

我想从这个页面解析一些数据:http: //www.bbc.co.uk/radio1/programmes/schedules/england/2013/03/1.json

我要解析的数据是标题,但我不确定如何提取数据.这是我到目前为止所做的:

 import java.io.BufferedReader;
 import java.io.InputStream;
 import java.io.InputStreamReader;
 import java.net.HttpURLConnection;
 import java.net.URL;
 import org.json.simple.JSONObject;
 import org.json.simple.parser.JSONParser;

 public class Test
 {
    public Test() { }

    public static void main(String[] args)
    {
            URL url;
            HttpURLConnection connection = null;
            InputStream is = null;
            JSONParser parser = new JSONParser();

            try
            {
                    url = new URL("http://www.bbc.co.uk/radio1/programmes/schedules/england/2013/03/1.json");
                    connection = (HttpURLConnection) url.openConnection();
                    connection.setRequestMethod("GET");
                    connection.connect();
                    is = connection.getInputStream();
                    BufferedReader theReader = new BufferedReader(new InputStreamReader(is, "UTF-8"));
                    String reply;
                    while ((reply = theReader.readLine()) != null)
                    {
                            System.out.println(reply);
                            Object obj = parser.parse(reply);
                            JSONObject jsonObject = (JSONObject) obj;
                            String title = (String) jsonObject.get("time");
                            System.out.println(title);
                    }
            }
            catch (Exception e) {
                    e.printStackTrace();
            }
    }

}

这只是返回null.谁能告诉我需要改变什么？谢谢.

Answer 1

如果你读到了JSONObject#get(String)实际的javadoc HashMap.get(String),它就说明了

返回:指定键映射到的值,如果此映射不包含键的映射,则返回null

您的JSON不包含密钥的映射time.

编辑:

如果您的意思是title代替time,请使用JSON的这个摘录

{"schedule":{"service":{"type":"radio","key":"radio1","title":"BBC Radio 1",...

你需要首先得到schedulea JSONObject,然后service作为a JSONObject,然后title作为正常值String.根据JSON值的类型应用此方法.