如果您正在使用Hibernate,您应该能够使用HQL,使用a not in和子查询(这是一个示例页面):
from Main as main where main.id not in (select map.main_id from Map as map)
Run Code Online (Sandbox Code Playgroud)
基于此页面,我相信您需要在Main.findAll方法中执行此查询:
def results = Main.findAll("from Main as main where main.id not in (select map.main_id from Map as map)")
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2515 次 |
| 最近记录: |