将Math.Pow与Microsoft Solver Foundation一起使用

Question

我正在做一个简单的求解器练习,我正在努力使用Math.Pow.

为什么我不能使用Math.Pow(error1, 2)以下几行？

error1 = error1 * error1;
error2 = error2 * error2;

它给出了一个错误:

错误3参数1:无法从'Microsoft.SolverFoundation.Services.Term'转换为'double'

相关代码:

using Microsoft.SolverFoundation.Common;
using Microsoft.SolverFoundation.Services;

... 

private void Form1_Load(object sender, EventArgs e)
{    
    var solver = SolverContext.GetContext();
    var model = solver.CreateModel();
    Decision R = new Decision(Domain.Real, "R");
    Decision T = new Decision(Domain.Real, "T");
    model.AddDecisions(R);
    model.AddDecisions(T);

    var xr1=5;
    var xr2=4;
    var xp1 = 6;
    var xp2=8;
    var error1 = xr1 * R + T - xp1;
    var error2 = xr2 * R + T - xp2;
    error1 = error1 * error1;
    error2 = error2 * error2;
    model.AddGoal("error",GoalKind.Minimize,error1+error2);

    var solution = solver.Solve();
    var valordeR = R.GetDouble();
    var valordeT = T.GetDouble();
}  

Answer 1

你可以使用Model.Power方法.Math.Pow仅限双打.

error1 = Model.Power(error1, 2);
error2 = Model.Power(error2, 2);