tho*_*asc 5 arrays resources save angularjs
我正在$resource使用查询从服务器检索数据.服务器返回一个对象数组,我存储在stuklijst中.我可以通过循环遍历数组并使用$ save将数组的每个项目发送回服务器,将stuklijst的(更新的)内容发送回服务器.我现在想要一次性将所有项目(整个stuklijst)发送到服务器,而不使用循环.
在stuklijst上尝试$ save时,Angular会抛出"destination.push不是函数"错误.如何实现这一目标$resource?
这是代码:
服务:
var stukModule = angular.module('stuklijstServices', ['ngResource'])
stukModule.factory('Stuklijsten', function($resource){
return $resource('rest/stuklijsten/:stuklijstID', {} );
});
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控制器:
//Get the data from server
$scope.stuklijst = Stuklijsten.query({stuklijstID: $routeParams.stuklijstID});
//See below for sample of data returned by server
//Users can update the data and request a save using saveStuklijst
//Send them back to server (using saveStuklijst(Stuklijst))
$scope.saveStuklijst = function(lijst) {
//sending items from stuklijst one by one :
for(var i = 0; i < lijst.length; i++)
{// console.log(i);
// console.dir(lijst[i]);
lijst[i].RowID = i
f = new Stuklijsten(lijst[i]);
f.$save({stuklijstID: $routeParams.stuklijstID});
} ;
};
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服务器返回的数据并存储在Stuklijst中:
[{"Name":"K FlxMT in DG met diameter 025 cm","LineType":0,"ProdID":"DG025KFLXMT","RowID":7,"Unit":"stk","Quantity":1},{"Name":"SPR Fl in DG met diameter 025 cm","LineType":0,"ProdID":"DG025SPRFL","RowID":8,"Unit":"stk","Quantity":1},{"Name":"T FlxFl in DG met diameter 025 cm","LineType":0,"ProdID":"DG025TFLXFL","RowID":9,"Unit":"stk","Quantity":0},{"Name":"VER PL EX in DG met diameter 025 cm","LineType":0,"ProdID":"DG025VERPLEX","RowID":10,"Unit":"stk","Quantity":0},{"Name":"K FlxMT in PV met diameter 008 cm","LineType":0,"ProdID":"PV008KFLXMT","RowID":11,"Unit":"stk","Quantity":0}]
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您可以通过重新定义资源的save函数来发送对象数组,以指定isArray=true如下:
stukModule.factory('Stuklijsten', ['$resource', function ($resource) {
return $resource(
'rest/stuklijsten/:stuklijstID',
{},
{
save: {
method: 'POST',
isArray: true
}
}
);
}]);
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然后,在您的控制器中,您可以组合列表并将所有内容保存在一个http请求中(不那么繁琐的API):
$scope.saveStuklijst = function(lijst) {
var some_list = [];
for(var i = 0; i < lijst.length; i++) {
lijst[i].RowID = i
f = new Stuklijsten(lijst[i]);
some_list.push({stuklijstID: $routeParams.stuklijstID});
};
Stuklijsten.save(some_list);
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如果您仍希望能够POST单个对象,则可以使用相同的概念创建一个saveBulk函数来保留save单个对象的原始对象.