我正在运行一个总是返回4行的MySQL查询:
row->name,row->date,row->ip,row->custom
我想要实现的是基于上面的结果创建一个简单的表,所以它看起来像:
{
"name" = result of row->name,
"date" = result of row->date,
"ip" = result of row->ip,
"custom" = result of row->custom
}
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我已经尝试了多种可能性,但发布的示例确实多种多样,我遇到了问题,使其正常工作.
我最后一次尝试不成功:
lua_createtable(L, 0, 4);
top = lua_gettop(L);
lua_pushstring(L, "name");
lua_pushstring(L, row->name);
lua_pushstring(L, "date");
lua_pushnumber(L, row->date);
lua_pushstring(L, "ip");
lua_pushstring(L, row->ip);
lua_pushstring(L, "custom");
lua_pushstring(L, row->custom);
lua_settable(L, top);
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Kam*_*olo 11
正如我在评论中提到的那样,lua_settable()只关注一key, value对.必须重复,如果您需要更多.
我更喜欢像这样保存Lua堆栈空间:
lua_createtable(L, 0, 4);
lua_pushstring(L, "name");
lua_pushstring(L, row->name);
lua_settable(L, -3); /* 3rd element from the stack top */
lua_pushstring(L, "date");
lua_pushstring(L, row->date);
lua_settable(L, -3);
lua_pushstring(L, "ip");
lua_pushstring(L, row->ip);
lua_settable(L, -3);
lua_pushstring(L, "custom");
lua_pushstring(L, row->custom);
lua_settable(L, -3);
/* We still have table left on top of the Lua stack. */
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此外,您可以编写某种C struct迭代器或其他东西.
注意:如果这是针对某种Lua包装器 - 您应该确保标准化的方式.在下面的示例中应用@lhf评论有关缩短它:
int
l_row_push(lua_State *l)
{
lua_createtable(L, 0, 4); /* creates and pushes new table on top of Lua stack */
lua_pushstring(L, row->name); /* Pushes table value on top of Lua stack */
lua_setfield(L, -2, "name"); /* table["name"] = row->name. Pops key value */
lua_pushstring(L, row->date);
lua_setfield(L, -2, "date");
lua_pushstring(L, row->ip);
lua_setfield(L, -2, "ip");
lua_pushstring(L, row->custom);
lua_setfield(L, -2, "custom");
/* Returning one table which is already on top of Lua stack. */
return 1;
}
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编辑:修正的使用lua_setfield()由@lhf音符.谢谢!