SKPaymentTransactionStatePurchased错误地多次调用

Question

我正在进行应用内购买,但我有一个我无法找到它的错误...

首先,我有一个按钮,当你点击它时,我的应用程序请求产品,捕获响应,你支付,你得到产品(一切正常).但这是我的问题.如果我点击按钮再次购买任何东西,我会收到两次警告,我买了两次.即使我第三次点击,我也会收到三次警报,我根据我点击的次数购买了三次,四次和五次.

所以看起来有些变量会一直存储请求.这是我的代码:

这会验证产品ID

- (void) validateProductIdentifiers
{ 
NSString *monedas = @" ID FROM PRODUCT ";
NSSet *product = [NSSet setWithObject:monedas];

productsRequest = [[SKProductsRequest alloc] initWithProductIdentifiers:product];

productsRequest.delegate = self;
[[SKPaymentQueue defaultQueue] addTransactionObserver:self];
[productsRequest start];
NSLog(@"STARTED REQUEST");
}

这可以处理Apple的响应

- (void)productsRequest:(SKProductsRequest *)request
 didReceiveResponse:(SKProductsResponse *)response
{


productsRequest=nil;

int found=0;

SKProduct *paraPagar;
skProducts = response.products;

for (SKProduct * skProduct in skProducts) {
             NSLog(@"Found product: %@ %@ %0.2f",
          skProduct.productIdentifier,
          skProduct.localizedTitle,
          skProduct.price.floatValue);
    found=1;

    paraPagar = skProduct;
}
if (found==1){ 
    payment = [SKMutablePayment paymentWithProduct:paraPagar];
    payment.quantity = 1;

    [[SKPaymentQueue defaultQueue]addPayment:payment];

}else{ 

 //error (not relevant code)

}
}

接受付款和完成交易

- (void)paymentQueue:(SKPaymentQueue *)queue
updatedTransactions:(NSArray *)transactions
{



for (SKPaymentTransaction *transaction in transactions) {
    switch (transaction.transactionState) {

        case SKPaymentTransactionStatePurchased:
            NSLog(@"BOUGHT");

            [[SKPaymentQueue defaultQueue] finishTransaction:transaction];
            [self completeTransaction:transaction];


            break;
        case SKPaymentTransactionStateFailed:
            NSLog(@"FAILED");
           [[SKPaymentQueue defaultQueue] finishTransaction:transaction];

            [self failedTransaction];
            break;
        case SKPaymentTransactionStateRestored:
            NSLog(@"RESTORED");
            //[self restoreTransaction:transaction];
            [[SKPaymentQueue defaultQueue] finishTransaction:transaction];
        case SKPaymentTransactionStatePurchasing:
            NSLog(@"PURCHASING");
        default:
            break;
    }

}

}

非常感谢您的宝贵时间!

Answer 1

修复了问题.

问题是,每次我点击按钮或更改视图时,观察者都会被复制.

解决方案是添加一个标志,以查看是否已添加观察者.

static bool hasAddObserver=NO;

PAYMENT METHOD{
if (!hasAddObserver) {
    [[SKPaymentQueue defaultQueue] addTransactionObserver:self];
    hasAddObserver=YES;
}
.....

Answer 2

我遇到了同样的问题，我会在 IAP 上点击购买，然后会收到来自 Apple 的多个回复和购买。

addTransactionObserver()每次我离开并通过viewDidLoad().

我需要取消观察它viewWillDisappear()：

override func viewWillDisappear() {
  SKPaymentQueue.defaultQueue().removeTransactionObserver(self)
}

我无法使用标志来阻止多个观察者，就像在 mursang 的回答中一样，因为我在其他视图中监听了事务。