C++模板专业化问题

Question

我的代码归结为:

//Just a templated array class .. implementation doesn't matter
template<int N>
struct Array {};

//A simple Traits like class
template<typename T>
struct MyTraits {}

//Specialization of the traits class
template<int N>
struct Foo< Array<N> >
{
  static void monkey() {};
}

int main()
{
  Foo< Array<3> >::monkey();
}

不幸的是编译器不喜欢它......

test.cpp: In function ‘int main()’:
test.cpp|17| error: ‘monkey’ is not a member of ‘Foo<Array<3> >’

我做错了什么,我该如何解决？谢谢

Answer 1

以下适用于我:

//Just a templated array class .. implementation doesn't matter
template<int N>
struct Array {};

//A simple Traits like class
template<typename T>
struct MyTraits {};

//Specialization of the traits class
template<int N>
struct MyTraits< Array<N> >
{
    static void monkey() {};
};

int main()
{
    MyTraits< Array<3> >::monkey();
}

你的方式Foo是不正确的,因为你可以看到我改变它以匹配评论.此外,在声明Foo/ 之后,您丢失了分号MyTraits.最后,对于数组类,我建议你使用它size_t作为类型N.