Laravel - 传递多个变量进行查看

Question

我有这个站点,其中一个页面从数据库中创建一个简单的人员列表.我需要将一个特定的人添加到我可以访问的变量中.

如何修改该return $view->with('persons', $persons);行以将$ ms变量传递给视图？

    function view($view)
    {
        $ms = Person::where('name', 'Foo Bar');

        $persons = Person::order_by('list_order', 'ASC')->get();

        return $view->with('persons', $persons);
    }

Answer 1

只需将其作为数组传递:

$data = [
    'name'  => 'Raphael',
    'age'   => 22,
    'email' => 'r.mobis@rmobis.com'
];

return View::make('user')->with($data);

或链接他们,就像@Antonio提到的那样.

Answer 2

这是你如何做到的:

function view($view)
{
    $ms = Person::where('name', '=', 'Foo Bar')->first();

    $persons = Person::order_by('list_order', 'ASC')->get();

    return $view->with('persons', $persons)->with('ms', $ms);
}

你也可以使用compact():

function view($view)
{
    $ms = Person::where('name', '=', 'Foo Bar')->first();

    $persons = Person::order_by('list_order', 'ASC')->get();

    return $view->with(compact('persons', 'ms'));
}

或者在一行中完成:

function view($view)
{
    return $view
            ->with('ms', Person::where('name', '=', 'Foo Bar')->first())
            ->with('persons', Person::order_by('list_order', 'ASC')->get());
}

或者甚至将其作为数组发送:

function view($view)
{
    $ms = Person::where('name', '=', 'Foo Bar')->first();

    $persons = Person::order_by('list_order', 'ASC')->get();

    return $view->with('data', ['ms' => $ms, 'persons' => $persons]));
}

但是,在这种情况下,您必须以这种方式访问​​它们:

{{ $data['ms'] }}

Answer 3

使用紧凑

function view($view)
{
    $ms = Person::where('name', '=', 'Foo Bar')->first();

    $persons = Person::order_by('list_order', 'ASC')->get();
    return View::make('users', compact('ms','persons'));
}

Answer 4

将多个变量传递给Laravel视图

//Passing variable to view using compact method    
$var1=value1;
$var2=value2;
$var3=value3;
return view('viewName', compact('var1','var2','var3'));

//Passing variable to view using with Method
return view('viewName')->with(['var1'=>value1,'var2'=>value2,'var3'=>'value3']);

//Passing variable to view using Associative Array
return view('viewName', ['var1'=>value1,'var2'=>value2,'var3'=>value3]);

阅读此处关于将数据传递给Laravel中的视图

Answer 5

这个答案似乎是

在函数中声明大量变量时有点帮助

拉拉维尔 5.7.*

例如

public function index()
{
    $activePost = Post::where('status','=','active')->get()->count();

    $inActivePost = Post::where('status','=','inactive')->get()->count();

    $yesterdayPostActive = Post::whereDate('created_at', Carbon::now()->addDay(-1))->get()->count();

    $todayPostActive = Post::whereDate('created_at', Carbon::now()->addDay(0))->get()->count();

    return view('dashboard.index')->with('activePost',$activePost)->with('inActivePost',$inActivePost )->with('yesterdayPostActive',$yesterdayPostActive )->with('todayPostActive',$todayPostActive );
}

当你看到返回的最后一行时，它看起来不太好

当你的项目变得越来越大时，这并不好

所以

public function index()
    {
        $activePost = Post::where('status','=','active')->get()->count();

        $inActivePost = Post::where('status','=','inactive')->get()->count();

        $yesterdayPostActive = Post::whereDate('created_at', Carbon::now()->addDay(-1))->get()->count();

        $todayPostActive = Post::whereDate('created_at', Carbon::now()->addDay(0))->get()->count();

        $viewShareVars = ['activePost','inActivePost','yesterdayPostActive','todayPostActive'];

        return view('dashboard.index',compact($viewShareVars));
    }

正如您所看到的，所有变量都声明为数组$viewShareVars并在视图中访问

但我的功能变得非常大，所以我决定让这条线变得 非常简单

public function index()
    {
        $activePost = Post::where('status','=','active')->get()->count();

        $inActivePost = Post::where('status','=','inactive')->get()->count();

        $yesterdayPostActive = Post::whereDate('created_at', Carbon::now()->addDay(-1))->get()->count();

        $todayPostActive = Post::whereDate('created_at', Carbon::now()->addDay(0))->get()->count();

        $viewShareVars = array_keys(get_defined_vars());

        return view('dashboard.index',compact($viewShareVars));
    }

原生 php 函数从函数中get_defined_vars() 获取所有定义的变量

并array_keys 会获取变量名称

所以在你看来你可以访问函数内所有声明的变量

作为{{$todayPostActive}}