使用OpenCV的Sobel操作计算图像梯度方向

CVi*_*ous 4 opencv image-processing computer-vision

我试图使用OpenCV的Sobel方法的结果确定图像梯度方向.

我理解这应该是一个非常简单的任务,我想我理解这个理论,但实现这个比我想象的更具挑战性.

我希望渐变方向在0-360度之间,但是我的代码显示所有渐变都在180到270度之间.

我提交了此代码的先前版本,其中包含整数除法问题.我已经解决了这个问题,但它没有解决限制角度方向的问题.

我已经完成了所有代码,但我无法看到我出错的地方?谁能发现我的错误?

谢谢.

void getGradients(IplImage* original, cv::Mat* gradArray)
{
cv::Mat original_Mat(original, true);

// Convert it to gray
cv::cvtColor( original_Mat, original_Mat, CV_RGB2GRAY );
//cv::blur(original_Mat, original_Mat, cv::Size(7,7));

/// Generate grad_x and grad_y
cv::Mat grad_x = cv::Mat::zeros(original->height, original->width, CV_16S); 
cv::Mat grad_y = cv::Mat::zeros(original->height, original->width, CV_16S);

/// Gradient X
cv::Sobel(original_Mat, grad_x, CV_16S, 1, 0, 3);

/// Gradient Y
cv::Sobel(original_Mat, grad_y, CV_16S, 0, 1, 3);

uchar* pixelX = grad_x.data;
uchar* pixelY = grad_y.data;
uchar* grad1 = gradArray[0].data;
uchar* grad2 = gradArray[1].data;
uchar* grad3 = gradArray[2].data;
uchar* grad4 = gradArray[3].data;
uchar* grad5 = gradArray[4].data;
uchar* grad6 = gradArray[5].data;
uchar* grad7 = gradArray[6].data;
uchar* grad8 = gradArray[7].data;
int count = 0;
int min = 999999;
int max = -1;

for(int i = 0; i < grad_x.rows * grad_x.cols; i++) 
{
        double directionRAD = atan2(pixelY[i], pixelX[i]);
        int directionDEG = (int)(180 + directionRAD / M_PI * 180);

        if(directionDEG < min){min = directionDEG;}
        if(directionDEG > max){max = directionDEG;}

        if(directionDEG >= 0 && directionDEG <= 45)         { grad1[i] = 255; count++;}         
        if(directionDEG >= 45 && directionDEG <= 90)        { grad2[i] = 255; count++;}         
        if(directionDEG >= 90 && directionDEG <= 135)       { grad3[i] = 255; count++;}         
        if(directionDEG >= 135 && directionDEG <= 190)      { grad4[i] = 255; count++;}         
        if(directionDEG >= 190 && directionDEG <= 225)      { grad5[i] = 255; count++;}         
        if(directionDEG >= 225 && directionDEG <= 270)      { grad6[i] = 255; count++;}     
        if(directionDEG >= 270 && directionDEG <= 315)      { grad7[i] = 255; count++;}
        if(directionDEG >= 315 && directionDEG <= 360)      { grad8[i] = 255; count++;}

        if(directionDEG < 0 || directionDEG > 360)
        {
            cout<<"Weird gradient direction given in method: getGradients.";
        }

}
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}

Bul*_*ull 7

grad_x并且grad_y是类型为CV_16SC1的Mats,即它们中的每个像素占用两个字节.

但是,您声明pixelXpixelY指向8位字节.因此pixelX[1]是第一个渐变的第二个字节,而不是第二个渐变.

你需要

short* pixelX = grad_x.ptr<short>(0);
short* pixelY = grad_y.ptr<short>(0);
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  • 你习惯在.data上直接迭代会在你遇到一个非连续的Mat时苦苦挣扎 - 请参阅http://docs.opencv.org/doc/tutorials/core/how_to_scan_images/how_to_scan_images.html#the-efficient -办法 (2认同)