Java: unparseable date exception

Question

While trying to transform the date format I get an exception:unparseable date and don't know how to fix this problem.

I am receiving a string which represents an event date and would like to display this date in different format in GUI.

What I was trying to do is the following:

private String modifyDateLayout(String inputDate){
        try {
            //inputDate = "2010-01-04 01:32:27 UTC";
            Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z").parse(inputDate);
            return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
        } catch (ParseException e) {
            e.printStackTrace();
            return "15.01.2010";
        }
    }

Anyway the line

String modifiedDateString = originalDate.toString();

is dummy. I would like to get a date string in the following format:

dd.MM.yyyy HH:mm:ss

and the input String example is the following:

2010-01-04 01:32:27 UTC

Does anyone know how to convert the example date (String) above into a String format dd.MM.yyyy HH:mm:ss?

Thank you!

编辑:我修复了错误的输入日期格式,但它仍然无法正常工作.上面是粘贴的方法,下面是调试会话的屏幕图像.

替代文字http://img683.imageshack.us/img683/193/dateproblem.png

#Update 我跑了

String[] timezones = TimeZone.getAvailableIDs();

并且数组中有UTC字符串.这是一个奇怪的问题.

我做了一个有效的肮脏黑客:

private String modifyDateLayout(String inputDate){
    try {
        inputDate = inputDate.replace(" UTC", "");
        Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(inputDate);
        return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
    } catch (ParseException e) {
        e.printStackTrace();
        return "15.01.2010";
    }
}

但我仍然希望在不缩短时区的情况下转换原始输入.

此代码是使用JDK 1.6为Android手机编写的.

Answer 1

你在这里基本上做的是依靠Date#toString()已经有固定模式的东西.要将Java Date对象转换为另一种人类可读的String模式,您需要SimpleDateFormat#format().

private String modifyDateLayout(String inputDate) throws ParseException{
    Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z").parse(inputDate);
    return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
}

顺便说一句,这里只能抛出"不可解析的日期"异常SimpleDateFormat#parse().这意味着它inputDate不是预期的模式"yyyy-MM-dd HH:mm:ss z".您可能需要修改模式以匹配inputDate实际模式.

更新:好的,我做了一个测试:

public static void main(String[] args) throws Exception {
    String inputDate = "2010-01-04 01:32:27 UTC";
    String newDate = new Test().modifyDateLayout(inputDate);
    System.out.println(newDate);
}

这正确打印:

03.01.2010 21:32:27

(我在GMT-4上)

更新2:根据你的编辑,你真的得到了ParseException.最可疑的部分将是时区UTC.这在Java环境中实际上是否已知？您使用的Java版本和操作系统版本是什么？检查TimeZone.getAvailableIDs().必须有一个UTC之间英寸