如何在c中的主脑猜谜游戏中正确统计"白色"？

Question

"白色"是在错误的位置检查正确的数字.但我不知道如何正确计算它.

#include "stdafx.h"
#include "stdlib.h" 
#include "time.h"

int _tmain(int argc, _TCHAR* argv[])
{
    int answer[4];
    int guess[4];
    int count = 0;

    srand(time(NULL)); 
    /*answer[0] = (rand() % 6)+1;
    answer[1] = (rand() % 6)+1;
    answer[2] = (rand() % 6)+1;
    answer[3] = (rand() % 6)+1;*/

    answer[0] = 3;
    answer[1] = 3;
    answer[2] = 5;
    answer[3] = 2;

    printf("%d %d %d %d\n", answer[0],  answer[1],  answer[2],  answer[3]);
    printf("          B W\n"); 

    do
    {
        int black = 0;
        int white = 0;
        count++;
        printf("Enter 4 numbers, this is your %d guess: ", count);
        scanf("%d %d %d %d", &guess[0], &guess[1], &guess[2], &guess[3]);
        printf("\n%d %d %d %d\n", guess[0], guess[1], guess[2], guess[3]);

        int g2[2][6];

        for (int a = 0;a < 4;a++)
            g2[0][a]=answer[a];

        for (int i = 0;i < 4;i++)
            g2[1][i]=guess[i];

        if (answer[0]==guess[0])
            black++;
        if (answer[1]==guess[1])
            black++;
        if (answer[2]==guess[2])
            black++;
        if (answer[3]==guess[3])
            black++;

        if (answer[1]==guess[0] || answer[2]==guess[0] || answer[3]==guess[0])
            white++;
        if (answer[0]==guess[1] || answer[2]==guess[1] || answer[3]==guess[1])
            white++;
        if (answer[0]==guess[2] || answer[1]==guess[2] || answer[3]==guess[2])
            white++;
        if (answer[0]==guess[3] || answer[1]==guess[3] || answer[2]==guess[3])
            white++;

        if (black==4)
            white=0;

        g2[1][4]=black;
        g2[1][5]=white;

        for (int n = 0;n < 6;n++)
            printf(" %d",g2[1][n]); 

        printf("\n");
    }
    while (answer[0]!=guess[0] || answer[1]!=guess[1] ||
           answer[2]!=guess[2] || answer[3]!=guess[3]);

    printf("BINGO!!!\n");

    return 0;
}

---

更新2:

for (int slot=0;slot<4;slot++)
{
    if (guess[slot] == answer[slot]) 
        black++;
    else 
        for (int s=0;s<4;s++)
            if (s != slot) 
            {
                if (guess[slot] == answer[s]) 
                    white++;
                break;
            }
}

---

更新3:

for (int x=0;x<4;x++)
flag[x]=0;

for (int slot = 0;slot < 4;slot++) 
{ 
    if (guess[slot] == answer[slot])  
        if (flag[slot]==1)
            black++; 
    else  
        for (int s=0;s < 4;s++) 
            if (s != slot)  
            { 
                if (guess[slot] == answer[s])
                    if (flag[s]==1)
                    {
                        white++; 
                        break; 
                    }
            } 
} 

---

更新4

for (int x=0;x<4;x++)
flag[x]=0;

for (int slot = 0;slot < 4;slot++) 
{ 
    if (guess[slot] == answer[slot])  {
        black++; 
        flag[slot]=1;
    }
else  
    for (int s=0;s < 4;s++)
        if (s != slot)
        { 
            if (guess[slot] == answer[s])  
            {
                white++; 
                flag[s]=1;
                break; 
            }
        } 
} 

---

更新5:

#include "stdafx.h"
#include "stdlib.h" 
#include "time.h"

int _tmain(int argc, _TCHAR* argv[])
{
    int answer[4];
    int guess[4];
    int flag[4];
    int count = 0;

    srand(time(NULL)); 
    /*answer[0] = (rand() % 6)+1;
    answer[1] = (rand() % 6)+1;
    answer[2] = (rand() % 6)+1;
    answer[3] = (rand() % 6)+1;*/

    answer[0] = 1;
    answer[1] = 2;
    answer[2] = 3;
    answer[3] = 4;

    printf("%d %d %d %d\n", answer[0],  answer[1],  answer[2],  answer[3]); 

    do
    {
        int black = 0;
        int white = 0;
        count++;
        printf("Enter 4 numbers, this is your %d guess: ", count);
        scanf("%d %d %d %d", &guess[0], &guess[1], &guess[2], &guess[3]);

        int g2[2][6];

        for (int a = 0;a < 4;a++)
            g2[0][a]=answer[a];

        for (int i = 0;i < 4;i++)
            g2[1][i]=guess[i];

        for (int x=0;x<4;x++)
            flag[x]=0;

        for (int slot = 0;slot < 4;slot++) 
        { 
            if (guess[slot] == answer[slot])  
                black++; 
            else   
                for (int s=0;s < 4;s++)  
                    if (s != slot && guess[slot] == answer[s] && !flag[s]) 
                    {  
                        white++;  
                        flag[s]=1; 
                        break;  
                    }
        } 

        g2[1][4]=black;
        g2[1][5]=white;

        printf("Guess %d: ", count);

        for (int n = 0;n < 4;n++){
            printf(" %d",g2[1][n]);
        }

        printf(" Black: %d White: %d\n", g2[1][4], g2[1][5]);
        printf("\n");
    }
    while (answer[0]!=guess[0] || answer[1]!=guess[1] ||
           answer[2]!=guess[2] || answer[3]!=guess[3]);

    printf("BINGO!!!\n");

    return 0;
}

Answer 1

Knuth在The Computer中作为Master Mind回答了这个问题并承认很难完全定义它.他暗示:

1. 通过将答案中的每个位置与当前猜测中的相同位置进行比较来计算黑色的数量.
2. 计算白人加黑人的数量,如下所示.
3. 从(2)中减去(1)得到白人的数量.

计算白人加黑人:

1. 制作两个数组,ans并guess为每种颜色添加一个插槽.
2. 对于每种颜色,请ans在答案中填充该颜色的桩数.同样,guess在当前猜测中填充该颜色的钉子数量.
3. 添加了min(ans[i], guess[i])每个i.这是白人加黑人.