无法识别的选择器发送到实例

Question

我在选择通知方法时遇到问题.

在init中我已经定义了这个:

NSNotificationCenter *nc = [NSNotificationCenter defaultCenter];
[nc addObserver:self selector:@selector(stopSyncIndicator:) name:IOS_STOP_SYNC_INDICATOR object:nil];

不过,在头文件和相同的实现中都定义了该方法:

-(void)stopSyncIndicator
{
    [indicator stopAnimating];
}

但是,当其他班级发布此通知时:

NSNotification *note = [NSNotification notificationWithName:IOS_STOP_SYNC_INDICATOR object:nil];
[[NSNotificationCenter defaultCenter] postNotification:note];

地狱破裂了:

[FTRecordViewController stopSyncIndicator:]: unrecognized selector sent to instance 0x8d3bc00
2013-11-18 13:47:06.994 [1835:70b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[FTRecordViewController stopSyncIndicator:]: unrecognized selector sent to instance 0x8d3bc00'
*** First throw call stack:
(
    0   CoreFoundation                      0x01bf75e4 __exceptionPreprocess + 180
    1   libobjc.A.dylib                     0x018f88b6 objc_exception_throw + 44
    2   CoreFoundation                      0x01c94903 -[NSObject(NSObject) doesNotRecognizeSelector:] + 275

知道这里发生了什么吗？

Answer 1

您的选择器:指示它将接受参数,您的实现不会

或

@selector(stopSyncIndicator) //no :

要么

-(void)stopSyncIndicator:(NSNotification *)notification //accept argument 

会解决这个问题