如何在ggplot2中使用斜体标签的斜体？

Question

我试图在ggplot2中使用斜体名称的斜体.我首先订购并重命名方面.我遇到了一个潜在的解决方案,但这需要labeller=label_parsed我labeller=name_labeller用来重命名我的方面.

在下面的例子中,我希望facet名称"one""two""three""four"和"five"为斜体.这是一个示例数据帧:

structure(list(Names = c(1L, 1L, 2L, 2L, 3L, 3L, 4L, 4L, 5L, 
5L, 6L, 6L, 7L, 7L, 8L, 8L, 9L, 9L, 10L, 10L), Other = c(5L, 
3L, 2L, 6L, 5L, 4L, 5L, 4L, 5L, 3L, 2L, 6L, 5L, 4L, 5L, 4L, 4L, 
5L, 3L, 2L), X = c(0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 
0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L), Y = c(0L, 10L, 
0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 0L, 10L, 
0L, 10L, 0L, 10L)), .Names = c("Names", "Other", "X", "Y"), class = "data.frame", row.names = c(NA, 
-20L))

并且生成该图的代码是

library(ggplot2)
library(grid)
vplayout <- function(x, y) viewport(layout.pos.row = x, layout.pos.col = y)



facets <- c("1", "2", "3", "4", "5")

names <- list(
  '1'="one",
  '2'="two",
  '3'="three",
  '4'="four",
  '5'="five"
)

name_labeller <- function(variable,value){
  return(names[value])
}

ggplot(FacetTestData[FacetTestData$Names %in% facets,], aes(y = Y, x = X, group = Names)) + 
  geom_point(shape = 21, size=3) + 
  scale_fill_manual(values=c("gray90","gray40")) + 
  geom_smooth(method="lm", se= FALSE, size = 1) +
  scale_color_manual(values=c("black","black")) +
  geom_smooth(method = 'lm', size = 1, colour = 'red', se = FALSE)  +
  facet_grid(Names ~ ., labeller=name_labeller)

以下代码显示为列表提供斜体属性 names

levels(names) <- c("italic('one')", "italic('two')", "italic('three')", "italic('four')",    "italic('five')")

但我无法弄清楚如何使用它facet_grid().有谁知道我怎么做到这一点？

Answer 1

这些方面的东西应该有效:

... + theme(strip.text = element_text(face = "italic"))

有关更多详细信息,请参阅文档theme().