如何在bash上运行mysql命令？

Question

以下代码适用于命令行

mysql --user='myusername' --password='mypassword' --database='mydatabase' --execute='DROP DATABASE myusername; 
CREATE DATABASE mydatabase;'

但是,它在执行bash文件时不起作用

#!/bin/bash
user=myusername
password=mypassword
database=mydatabase

mysql --user='$user' --password='$password' --database='$database' --execute='DROP DATABASE $user; CREATE DATABASE $database;'

我收到以下错误:

ERROR 1045(28000):用户'$ user'@'localhost'拒绝访问(使用密码:YES)

如何使bash文件作为命令行运行？

Answer 1

使用BASH变量时使用双引号.

mysql --user="$user" --password="$password" --database="$database" --execute="DROP DATABASE $user; CREATE DATABASE $database;"

BASH不会在单引号中扩展变量.

Answer 2

当$ user和$ password超出单引号时,这个有效,双引号.单引号语句中的单引号.

mysql --user="$user" --password="$password" --database="$user" --execute='DROP DATABASE '$user'; CREATE DATABASE '$user';'

Answer 3

我编写了一个 shell 脚本，它将从属性文件中读取数据，然后在 shell 脚本上运行 mysql 脚本。分享这个可能对其他人有帮助。

#!/bin/bash
    PROPERTY_FILE=filename.properties

    function getProperty {
       PROP_KEY=$1
       PROP_VALUE=`cat $PROPERTY_FILE | grep "$PROP_KEY" | cut -d'=' -f2`
       echo $PROP_VALUE
    }

    echo "# Reading property from $PROPERTY_FILE"
    DB_USER=$(getProperty "db.username")
    DB_PASS=$(getProperty "db.password")
    ROOT_LOC=$(getProperty "root.location")
    echo $DB_USER
    echo $DB_PASS
    echo $ROOT_LOC
    echo "Writing on DB ... "
    mysql -u$DB_USER -p$DB_PASS dbname<<EOFMYSQL

    update tablename set tablename.value_ = "$ROOT_LOC" where tablename.name_="Root directory location";
    EOFMYSQL
    echo "Writing root location($ROOT_LOC) is done ... "
    counter=`mysql -u${DB_USER} -p${DB_PASS} dbname -e "select count(*) from tablename where tablename.name_='Root directory location' and tablename.value_ = '$ROOT_LOC';" | grep -v "count"`;

    if [ "$counter" = "1" ]
    then
    echo "ROOT location updated"
    fi