Nic*_*las 19 postgresql postgresql-9.1
如果我有下表:
Table "users"
Column | Type | Modifiers
---------------+------------------+-----------
id | integer | not null default nextval('users_id_seq'::regclass)
monthly_usage | real[] |
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monthly_usage12个数字的数组在哪里,即{1.2, 1.3, 6.2, 0.9,...}
如何选择该列的总和?
有点像:
SELECT id, sum(monthly_usage) as total_usage from users;
这显然不起作用.
小智 32
SELECT id, (SELECT SUM(s) FROM UNNEST(monthly_usage) s) as total_usage from users;
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这种概括和重新格式化Dmitry的答案有助于我理解它的工作原理:
SELECT
sum(a) AS total
FROM
(
SELECT
unnest(array [1,2,3]) AS a
) AS b
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结果:
total
6
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