问题的例子
date X Y
2012-07-05 00:01:19 0.0122 NA
2012-07-05 03:19:34 0.0121 NA
2012-07-05 03:19:56 0.0121 0.027
2012-07-05 03:20:31 0.0121 0.027
2012-07-05 04:19:56 0.0121 0.028
2012-07-05 04:20:31 0.0121 0.028
2012-07-05 04:20:50 0.0121 0.028
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我怎样才能填补NA与0.027在Y列?
您可以使用na.locf"zoo"包:
library(zoo)
na.locf(mydf, fromLast=TRUE)
# X Y
# 1 0.0122 0.027
# 2 0.0121 0.027
# 3 0.0121 0.027
# 4 0.0121 0.027
# 5 0.0121 0.028
# 6 0.0121 0.028
# 7 0.0121 0.028
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其中"mydf"是:
mydf <- structure(list(X = c(0.0122, 0.0121, 0.0121, 0.0121, 0.0121,
0.0121, 0.0121), Y = c(NA, NA, 0.027, 0.027, 0.028, 0.028, 0.028)),
.Names = c("X", "Y"), class = "data.frame", row.names = c(NA, -7L))
mydf
# X Y
# 1 0.0122 NA
# 2 0.0121 NA
# 3 0.0121 0.027
# 4 0.0121 0.027
# 5 0.0121 0.028
# 6 0.0121 0.028
# 7 0.0121 0.028
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