__init __()得到了一个意外的关键字参数'user'

Question

我在创建用户时使用Django创建用户和对象.但是有一个错误

__init__() got an unexpected keyword argument 'user'

register()在view.py中调用函数时.功能是:

def register(request):  
    '''signup view'''     
    if request.method=="POST":  
        form=RegisterForm(request.POST)  
        if form.is_valid():  
            username=form.cleaned_data["username"]  
            email=form.cleaned_data["email"]  
            password=form.cleaned_data["password"]  
            user=User.objects.create_user(username, email, password)  
            user.save()
            return HttpResponseRedirect('/keenhome/accounts/login/')
        else: 
            form = RegisterForm()      
            return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))  

    #This is used for reinputting if failed to register    
    else: 
        form = RegisterForm()      
        return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))

对象类是:

class LivingRoom(models.Model):
    '''Living Room object'''
    user = models.OneToOneField(User)

    def __init__(self, temp=65):
        self.temp=temp

    TURN_ON_OFF = (
        ('ON', 'On'),
        ('OFF', 'Off'),
    )

    TEMP = (
        ('HIGH', 'High'),
        ('MEDIUM', 'Medium'),
        ('LOW', 'Low'),
    )

    on_off = models.CharField(max_length=2, choices=TURN_ON_OFF)
    temp = models.CharField(max_length=2, choices=TEMP)

#signal function: if a user is created, add control livingroom to the user    
def create_control_livingroom(sender, instance, created, **kwargs):
    if created:
        LivingRoom.objects.create(user=instance)

post_save.connect(create_control_livingroom, sender=User)

Django错误页面通知错误信息: user=User.objects.create_user(username, email, password) 和 LivingRoom.objects.create(user=instance)

我试图搜索这个问题,找到一些案例,但仍然无法弄清楚如何解决它.

Answer 1

你做不到

LivingRoom.objects.create(user=instance)

因为你有一个不__init__作为参数的init方法.

你想要的东西

#signal function: if a user is created, add control livingroom to the user    
def create_control_livingroom(sender, instance, created, **kwargs):
    if created:
        my_room = LivingRoom()
        my_room.user = instance

Answer 2

我得到了同样的错误.

在我看来,我是这样重写get_form_kwargs():

class UserAccountView(FormView):
    form_class = UserAccountForm
    success_url = '/'
    template_name = 'user_account/user-account.html'

def get_form_kwargs(self):
    kwargs = super(UserAccountView, self).get_form_kwargs()
    kwargs.update({'user': self.request.user})
    return kwargs

但在我的表单上,我无法覆盖init()方法.一旦我做到了.问题解决了

class UserAccountForm(forms.Form):
    first_name = forms.CharField(label='Your first name', max_length=30)
    last_name = forms.CharField(label='Your last name', max_length=30)
    email = forms.EmailField(max_length=75)

    def __init__(self, *args, **kwargs):
        user = kwargs.pop('user')
        super(UserAccountForm, self).__init__(*args, **kwargs)

Answer 3

LivingRoom.objects.create()调用LivingRoom.__init__()- 如果您阅读了回溯，您可能已经注意到 - 向其传递相同的参数。长话短说，Djangomodels.Model子类的初始值设定项最好单独保留，或者应该接受与模型元字段匹配的 *args 和 **kwargs。为字段提供默认值的正确方法是在字段构造函数中使用关键字，default如 FineManual 中所述。