Gau*_*ora 5 android listview horizontalscrollview
我有一个包含20行的列表视图,我想为scrollview
列表视图中的每个行项设置一个水平,因为每行包含多个项目.
这是我的代码:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:orientation="horizontal" >
<HorizontalScrollView
android:id="@+id/hor_scroll"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:scrollbars="none" >
<LinearLayout
android:id="@+id/mainLinear"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:orientation="horizontal" >
</LinearLayout>
</HorizontalScrollView>
</RelativeLayout>
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内行布局,可以连续多次复制
<ImageView
android:id="@+id/icon"
android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:layout_marginRight="6.0dip"
android:src="@drawable/ic_launcher" />
<TextView
android:id="@+id/text"
android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:gravity="center_vertical"
android:text="Example Value"
android:textAppearance="?android:textAppearanceMedium" />
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BaseAdapter
public class HorizontalListViewAdapter extends BaseAdapter {
private Context context;
private ArrayList<ArrayList<DwivediJi>> dataSet;
public HorizontalListViewAdapter(Context context) {
this.context = context;
}
@Override
public int getCount() {
return 20;
}
@Override
public Object getItem(int arg0) {
// TODO Auto-generated method stub
return arg0;
}
@Override
public long getItemId(int arg0) {
// TODO Auto-generated method stub
return arg0;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = inflater.inflate(R.layout.horizontal_list_item, null,false);
LinearLayout mainLinnerLayout=(LinearLayout)convertView.findViewById(R.id.mainLinear);
for (int i = 0; i <5; i++) {
View additionView = inflater.inflate(R.layout.inner_layout_file, null,false);
LinearLayout innerLinnerLayout=(LinearLayout)additionView.findViewById(R.id.inner_layout);
mainLinnerLayout.addView(innerLinnerLayout);
}
return convertView;
}
class ViewHolder {
TextView tv_titleExample;
HorizontalScrollView hzView;
LinearLayout linear_layout,main_linear_layout;
}
}
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我的问题
看看附带的截图.我的问题是每行中一次显示多个视图.
我希望一次只能向用户显示一个视图,其余用户要做的就是从左到右或从右到左滑动.
注意:不是一个理想的解决方案,但应该提供您想要的。另一个注意:这可能会使您的列表视图稍微卡顿,具体取决于布局复杂性
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = inflater.inflate(R.layout.horizontal_list_item, null,false);
LinearLayout mainLinnerLayout=(LinearLayout)convertView.findViewById(R.id.mainLinear);
for (int i = 0; i <5; i++) {
View additionView = inflater.inflate(R.layout.inner_layout_file, null,false);
LinearLayout innerLinnerLayout=(LinearLayout)additionView.findViewById(R.id.inner_layout);
// If the width varies for each innerLinnerLayout, then remove the if block & always calculate padding value
// padding is an integer initialized to -1 in the constructor
if (padding == -1) {
int width = context.getResources().getDisplayMetrics().widthPixels;
innerLinnerLayout.measure(MeasureSpec.UNSPECIFIED, MeasureSpec.UNSPECIFIED);
padding = width - additionView.getMeasuredWidth();
}
// I've set padding to right only, but you could center it by giving left and right padding of value=(padding/2)
innerLinnerLayout.setPadding(0, 0, padding, 0);
mainLinnerLayout.addView(innerLinnerLayout);
}
return convertView;
}
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