以编程方式获取Android手机模型

And*_*ega 328 android android-hardware

我想知道是否有办法在Android中以编程方式阅读手机模型.

我想得到像HTC Dream,Milestone,Sapphire或其他任何东西......

Ido*_*lon 411

我使用以下代码来获取完整的设备名称.它获取模型和制造商字符串并连接它们,除非模型字符串已包含制造商名称(在某些手机上它):

public String getDeviceName() {
    String manufacturer = Build.MANUFACTURER;
    String model = Build.MODEL;
    if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
        return capitalize(model);
    } else {
        return capitalize(manufacturer) + " " + model;
    }
}


private String capitalize(String s) {
    if (s == null || s.length() == 0) {
        return "";
    }
    char first = s.charAt(0);
    if (Character.isUpperCase(first)) {
        return s;
    } else {
        return Character.toUpperCase(first) + s.substring(1);
    }
} 
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以下是我从用户处获得的设备名称的几个示例:

三星GT-S5830L
摩托罗拉MB860
索尼爱立信LT18i
LGE LG-P500
HTC Desire V
HTC Wildfire S A510e
...

  • @evilfish从Google上试用此列表:https://support.google.com/googleplay/answer/1727131 (7认同)
  • 我不明白为什么 Google 不包含诸如 Build.MARKET_NAME 之类的内容 (3认同)

Jar*_*ler 304

在许多流行的设备上,设备的市场名称不可用.例如,在三星Galaxy S6的价值Build.MODEL可能是"SM-G920F","SM-G920I""SM-G920W8".

我创建了一个小型库,可以获得设备的市场(消费者友好)名称.它获得超过10,000个设备的正确名称,并不断更新.如果您想使用我的图书馆,请点击以下链接:

Github上的AndroidDeviceNames库


如果您不想使用上面的库,那么这是获取消费者友好设备名称的最佳解决方案:

/** Returns the consumer friendly device name */
public static String getDeviceName() {
  String manufacturer = Build.MANUFACTURER;
  String model = Build.MODEL;
  if (model.startsWith(manufacturer)) {
    return capitalize(model);
  }
  return capitalize(manufacturer) + " " + model;
}

private static String capitalize(String str) {
  if (TextUtils.isEmpty(str)) {
    return str;
  }
  char[] arr = str.toCharArray();
  boolean capitalizeNext = true;

  StringBuilder phrase = new StringBuilder();
  for (char c : arr) {
    if (capitalizeNext && Character.isLetter(c)) {
      phrase.append(Character.toUpperCase(c));
      capitalizeNext = false;
      continue;
    } else if (Character.isWhitespace(c)) {
      capitalizeNext = true;
    }
    phrase.append(c);
  }

  return phrase.toString();
}
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我的Verizon HTC One M8示例:

// using method from above
System.out.println(getDeviceName());
// Using https://github.com/jaredrummler/AndroidDeviceNames
System.out.println(DeviceName.getDeviceName());
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结果:

HTC6525LVW

HTC One(M8)

  • 谢谢Jared.我今天需要这个,但是对于Xamarin.Android这样将你的文件翻译成C#.如果有人需要它,你可以在这里找到它.https://gist.github.com/mohibsheth/5e1b361ae49c257b8caf (18认同)

Mir*_* N. 112

是的:Build.MODEL.

  • 是的,这就是模拟器的型号。请注意,它甚至对内部存储使用类似的名称。 (3认同)

Fal*_*65o 32

实际上,这不是100%正确.这可以给你模型(有时候数字).
将为您提供手机制造商(您的要求的HTC部分):

 Build.MANUFACTURER
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对于产品名称:

 Build.PRODUCT
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  • 我发现`String name = Build.MANUFACTURER +" - "+ Build.MODEL`是最有用的组合.Build.PRODUCT有时会使用意外的名称.例如,在Galaxy Nexus上,它返回"takgu".另一方面,Build.MODEL是在Settings-> About Phone-> Model number下显示的面向用户的值. (7认同)

ruX*_*ruX 26

寻找完整的属性列表的人Build是Sony Z1 Compact的一个例子:

Build.BOARD = MSM8974
Build.BOOTLOADER = s1
Build.BRAND = Sony
Build.CPU_ABI = armeabi-v7a
Build.CPU_ABI2 = armeabi
Build.DEVICE = D5503
Build.DISPLAY = 14.6.A.1.236
Build.FINGERPRINT = Sony/D5503/D5503:5.1.1/14.6.A.1.236/2031203XXX:user/release-keys
Build.HARDWARE = qcom
Build.HOST = BuildHost
Build.ID = 14.6.A.1.236
Build.IS_DEBUGGABLE = false
Build.MANUFACTURER = Sony
Build.MODEL = D5503
Build.PRODUCT = D5503
Build.RADIO = unknown
Build.SERIAL = CB5A1YGVMT
Build.SUPPORTED_32_BIT_ABIS = [Ljava.lang.String;@3dd90541
Build.SUPPORTED_64_BIT_ABIS = [Ljava.lang.String;@1da4fc3
Build.SUPPORTED_ABIS = [Ljava.lang.String;@525f635
Build.TAGS = release-keys
Build.TIME = 144792559XXXX
Build.TYPE = user
Build.UNKNOWN = unknown
Build.USER = BuildUser
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您可以使用kotlin使用"evaluate expression"对话框在调试模式下轻松列出设备的这些属性:

android.os.Build::class.java.fields.map { "Build.${it.name} = ${it.get(it.name)}"}.joinToString("\n")
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Aja*_*dya 13

String deviceName = android.os.Build.MODEL; // returns model name 

String deviceManufacturer = android.os.Build.MANUFACTURER; // returns manufacturer
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Sea*_*ean 12

Kotlin 简短版本:

import android.os.Build.MANUFACTURER
import android.os.Build.MODEL

fun getDeviceName(): String =
    if (MODEL.startsWith(MANUFACTURER, ignoreCase = true)) {
        MODEL
    } else {
        "$MANUFACTURER $MODEL"
    }.capitalize(Locale.ROOT)
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sil*_*ire 8

当您要检索制造商,设备名称和/或模型时,以下字符串都是有用的:

String manufacturer = Build.MANUFACTURER;
String brand        = Build.BRAND;
String product      = Build.PRODUCT;
String model        = Build.MODEL;
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Edw*_*ans 8

显然,您需要使用Google上的列表,网址https://support.google.com/googleplay/answer/1727131

API不会返回我期望的任何内容或设置中的任何内容.对于我的摩托罗拉X,这就是我得到的

   Build.MODEL = "XT1053"
   Build.BRAND = "motorola"
   Build.PRODUCT = "ghost"
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去上面提到的页面 "鬼"映射到Moto X.似乎这可能有点简单......


maj*_*han 8

Build.DEVICE // The name of the industrial design.
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Build.DEVICE为某些设备提供人类可读的名称Build.MODEL

Build.DEVICE = OnePlus6
Build.MANUFACTURER = OnePlus
Build.MODEL = ONEPLUS A6003
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小智 7

您可以使用以下代码获取设备的品牌名称和品牌型号.

 String brand = Build.BRAND; // for getting BrandName
 String model = Build.MODEL; // for getting Model of the device
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