Sim*_*urr 5 wordpress group-by custom-fields custom-post-type
我必须创建一个搜索表单,在其中必须按自定义帖子类型的状态填充选择。其中一些具有相同的状态,然后我想进行分组以获得一个干净的状态选择列表..我已经这样做了:
<?php
function query_group_by_filter($groupby){
global $wpdb;
return $wpdb->postmeta.".meta_key = 'state'";
}
?>
<?php add_filter('posts_groupby', 'query_group_by_filter'); ?>
<?php $states = new WP_Query(array('post_type' => 'observatoire')); ?>
<?php remove_filter('posts_groupby', 'query_group_by_filter'); ?>
<select id="" class="" name="siege_pays" >
<option value=""></option>
<?php
while ( $states->have_posts() ) : $states->the_post();
echo "<option value=".get_field_object('state').">".get_field_object('state')."</option>";
endwhile;
?>
</select>
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结果查询不起作用..请帮忙:)
'SELECT SQL_CALC_FOUND_ROWS wp_posts.ID FROM wp_posts WHERE 1=1 AND wp_posts.post_type = 'observatoire' AND ((wp_posts.post_status = 'publish' OR wp_posts.post_status = 'private') OR wp_posts.post_status = 'private') GROUP BY wp_postmeta.meta_key = 'siege_pays' ORDER BY wp_posts.post_date DESC LIMIT 0, 10'
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小智 1
您可以尝试下面的代码:
<?php
function query_group_by_filter($groupby){
global $wpdb;
return $wpdb->postmeta . '.meta_key = "state"';
}
?>
<?php add_filter('posts_groupby', 'query_group_by_filter'); ?>
<?php $states = new WP_Query(array(
'post_type' => 'observatoire',
'post_status' => 'publish',
'posts_per_page' => -1,
'meta_key' => 'state'
));
?>
<?php remove_filter('posts_groupby', 'query_group_by_filter'); ?>
<select id="" class="" name="siege_pays" >
<option value=""></option>
<?php
while ( $states->have_posts() ) : $states->the_post();
echo "<option value=".get_field_object('state').">".get_field_object('state')."</option>";
endwhile;
?>
</select>
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查询看起来像:
SELECT wp_posts.*
FROM wp_posts INNER JOIN wp_postmeta
ON (wp_posts.ID = wp_postmeta.post_id)
WHERE wp_posts.post_type = 'observatoire'
AND (wp_posts.post_status = 'publish')
AND (wp_postmeta.meta_key = 'state' )
GROUP BY wp_postmeta.meta_key = "state"
ORDER BY wp_posts.post_date DESC
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