cra*_*irk 8 sql oracle alias subquery
有没有办法在Oracle SQL查询中引用其中包含空格的别名?我还没有在任何地方找到它.通常我不使用空格来命名数据库元素,所以这对我来说是个新的基础.
这是一个示例查询:
SELECT t.id AS "Ticket ID",
(SELECT w.workgroup_title FROM workgroups w
WHERE w.operator_id = t.operator_id AND ROWNUM < 2) AS "Workgroup Title"
FROM tickets t
Run Code Online (Sandbox Code Playgroud)
如何在未来的比较操作中使用"Ticket ID"或"Workgroup Title"?例如:
"票证ID"== 9或"工作组标题"=='工作组#1'
我猜这是一个简单的方法,但还没有找到它.
谢谢!
PS这是传给我的遗产.SQL中的别名动态地绑定到其他各种代码中,并且都有空格.因此,删除空格并不是一件简单的事情,我目前还没有预算好时间.否则,这就是我要做的.
编辑澄清
使用上面的示例,如何在"工作组标题"始终引用别名的情况下执行此类操作:
SELECT t.id AS "Ticket ID",
(SELECT w.workgroup_title FROM workgroups w
WHERE w.operator_id = t.operator_id AND ROWNUM < 2) AS "Workgroup Title",
(SELECT s.support_tier_id FROM support_tiers s
WHERE s.workgroup_title == "Workgroup Title") AS "Support Tier ID"
FROM tickets t
Run Code Online (Sandbox Code Playgroud)
是的,你可以这样做,但你必须用双引号括起这些名字:
-- SQL Example
SELECT "Just one" FROM (
SELECT 1 AS "Just one" FROM dual
);
Run Code Online (Sandbox Code Playgroud)
输出:
Just one ---------- 1
-- PL/SQL Example
BEGIN
FOR v_rec IN (SELECT 1 AS "Just one" FROM dual)
LOOP
dbms_output.put_line(v_rec."Just one");
END LOOP;
END;
/
Run Code Online (Sandbox Code Playgroud)
输出:
1
还有一点好奇心:
BEGIN
FOR v_rec IN (SELECT COUNT(1) * 10 FROM dual)
LOOP
dbms_output.put_line(v_rec."COUNT(1)*10");
END LOOP;
END;
Run Code Online (Sandbox Code Playgroud)
这适用..并打印:
10
编辑
您可以在查询的其他位置引用别名列,例如:
SELECT 'It is just one' FROM (
SELECT "Just one" FROM (
SELECT 1 AS "Just one" FROM dual
) t
WHERE t."Just one" = 1 -- prefixing with t. is not necessary in this particular example
);
Run Code Online (Sandbox Code Playgroud)
输出:
It is just one