Bas*_*sel 7 php mysql sql performance
我有以下查询:
SELECT DISTINCT f1.match_static_id,
f2.comments_no,
f2.maxtimestamp,
users.username,
users.id,
matches_of_comments.localteam_name,
matches_of_comments.visitorteam_name,
matches_of_comments.localteam_goals,
matches_of_comments.visitorteam_goals,
matches_of_comments.match_status,
new_iddaa.iddaa_code
FROM comments AS f1
INNER JOIN (
SELECT match_static_id,
MAX( TIMESTAMP ) maxtimestamp,
COUNT( match_static_id ) AS comments_no
FROM comments
GROUP BY match_static_id
) AS f2 ON f1.match_static_id = f2.match_static_id
AND f1.timestamp = f2.maxtimestamp
INNER JOIN users ON users.id = f1.user_id
INNER JOIN matches_of_comments ON matches_of_comments.match_id = f2.match_static_id
LEFT JOIN new_iddaa ON new_iddaa.match_id = matches_of_comments.match_id
WHERE matches_of_comments.flag =1
ORDER BY f2.maxtimestamp DESC
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这是该查询的EXPLAIN计划:
+----+-------------+---------------------+--------+-----------------------------------+-----------+---------+------------------------------------------+-------+------------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | extra |
+----+-------------+---------------------+--------+-----------------------------------+-----------+---------+------------------------------------------+-------+------------------------------------------------+
| 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 542 | Using temporary; Using filesort |
| 1 | PRIMARY | f1 | ref | timestamp,match_static_id,user_id | timestamp | 4 | f2.maxtimestamp | 1 | Using where |
| 1 | PRIMARY | users | eq_ref | PRIMARY | PRIMARY | 4 | skormix_db1.f1.user_id | 1 | |
| 1 | PRIMARY | matches_of_comments | ALL | match_id | NULL | NULL | NULL | 20873 | Range checked for each record (index map: 0x8) |
| 1 | PRIMARY | new_iddaa | ref | match_id | match_id | 4 | skormix_db1.matches_of_comments.match_id | 1 | |
| 2 | DERIVED | comments | ALL | NULL | NULL | NULL | NULL | 933 | Using temporary; Using filesort |
+----+-------------+---------------------+--------+-----------------------------------+-----------+---------+------------------------------------------+-------+------------------------------------------------+
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如果此匹配至少有一条评论,我会使用此查询来获取匹配信息.
我得到了团队的名字,代码(iddaa代码),评论数量,最后一个commrnt的timstamp,最后一条评论的作者.
我有一个大型数据库,预计在接下来的几个月内会更大,我对MySQL查询非常新,我想确保我从一开始就使用优化查询,所以我想知道如何阅读这解释了使查询更好,更快的信息.
我看到表中有很多地方虽然我建了它们,但它们并没有使用索引.
我也看到在表列中派生,我不知道如何使这个查询更快,以及如何摆脱filesort因为我不能为派生查询制作索引?
我用索引(键)写下查询中使用表的结构,我希望能提前得到一些提示或简单的答案.
注释(f1)表结构是:
CREATE TABLE `comments` (
`id` int(25) NOT NULL AUTO_INCREMENT,
`comments` text COLLATE utf8_unicode_ci NOT NULL,
`timestamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`date` date NOT NULL,
`time` time NOT NULL,
`match_static_id` int(25) NOT NULL,
`ip` varchar(255) CHARACTER SET latin1 NOT NULL,
`comments_yes_or_no` int(25) NOT NULL,
`user_id` int(25) NOT NULL,
PRIMARY KEY (`id`),
KEY `timestamp` (`timestamp`),
KEY `match_static_id` (`match_static_id`),
KEY `user_id` (`user_id`)
) ENGINE=MyISAM AUTO_INCREMENT=935 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci
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用户表结构是:
CREATE TABLE `users` (
`id` int(25) NOT NULL AUTO_INCREMENT,
`username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`email` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`gender` int(25) NOT NULL,
`first_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`last_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`avatar` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`alert` int(25) NOT NULL,
`daily_tahmin` int(25) NOT NULL,
`monthly_tahmin` int(25) NOT NULL,
`admin` int(25) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=995 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci
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matches_of_comments_结构是:
CREATE TABLE `matches_of_comments` (
`id` int(25) NOT NULL AUTO_INCREMENT,
`en_tournament_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`tournament_id` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`country_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`match_status` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`match_time` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`match_date` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`static_id` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`fix_id` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`match_id` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`localteam_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`localteam_goals` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`localteam_id` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`visitorteam_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`visitorteam_goals` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`visitorteam_id` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`ht_score` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`flag` int(25) NOT NULL,
PRIMARY KEY (`id`),
KEY `match_status` (`match_status`),
KEY `match_date` (`match_date`),
KEY `match_id` (`match_id`),
KEY `localteam_id` (`localteam_id`),
KEY `visitorteam_id` (`visitorteam_id`),
KEY `flag` (`flag`)
) ENGINE=MyISAM AUTO_INCREMENT=237790 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci
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new_iddaa表结构是:
CREATE TABLE `new_iddaa` (
`id` int(25) NOT NULL AUTO_INCREMENT,
`match_id` int(25) NOT NULL,
`iddaa_code` int(25) NOT NULL,
`tv_channel` varchar(255) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL,
`skormix_tahmin` varchar(255) CHARACTER SET utf8 NOT NULL,
PRIMARY KEY (`id`),
KEY `match_id` (`match_id`)
) ENGINE=MyISAM AUTO_INCREMENT=8191 DEFAULT CHARSET=latin1
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在讨论选项之前,先从更紧迫的问题开始。
\n\n第一个迫在眉睫的问题是:
\n\nSELECT DISTINCT \xe2\x80\xa6\nRun Code Online (Sandbox Code Playgroud)\n\nAselect distinct很慢。非常非常慢:它基本上比较您的集合返回的每行的每个字段。ID当其中有一个保证每行都是唯一的时,自然有优化的空间,但您自己的查询看起来并没有提供任何这样的可能性:最多是来自matches_of_comments和 的元组new_iddaa元组。
要解决此问题,请将查询分成两个或更多部分,并仅获取您正在执行的操作实际需要的内容。这似乎是matches_of_comments按他们的最新评论日期排序,然后从users和获取额外的化妆品数据new_iddaa获取额外的化妆品数据。
恕我直言,下一个是最大的问题:
\n\nINNER JOIN (\n SELECT match_static_id,\n MAX( TIMESTAMP ) maxtimestamp,\n COUNT( match_static_id ) AS comments_no\n FROM comments\n GROUP BY match_static_id\n ) AS f2 ON f1.match_static_id = f2.match_static_id \n AND f1.timestamp = f2.maxtimestamp\nRun Code Online (Sandbox Code Playgroud)\n\n您正在将一个聚合与一个表连接起来(match_static_id, timestamp)没有索引的元组上的表连接起来,并从中获取一个巨大的集合。您有保证的合并连接 \xe2\x80\x94 不是您想要的。
最后一个令人瞠目结舌的问题是:
\n\nORDER BY f2.maxtimestamp DESC\nRun Code Online (Sandbox Code Playgroud)\n\n首先,你没有任何限制。这意味着您将构建、排序并返回一个巨大的集合。当然,您正在对这些数据进行分页,因此可以通过添加限制子句在查询中进行分页。
\n\n添加限制后,您需要考虑添加额外行的内容以及应如何对它们进行排序。根据你的架构,我想new_iddaa是的。您是否以这样的方式对事物进行分页:后面的信息需要成为该查询及其返回的行数的一部分?我想不会,因为您显然对这些行的排序方式不感兴趣。
扫描您的架构后,会弹出以下附加内容:
\n\n`match_id` varchar(255)\nRun Code Online (Sandbox Code Playgroud)\n\n引用它的行是整数,对吗?因此它也应该是一个整数,以避免将 varchar 转换为 int 或反之亦然的开销,并允许在任何一种情况下使用索引。
\n\n虽然与此特定查询无关,但以下两个字段也需要注意并进行正确的转换:
\n\n`tournament_id` varchar(255)\n`match_time` varchar(255)\n`match_date` varchar(255)\n`static_id` varchar(255)\n`fix_id` varchar(255)\n`localteam_id` varchar(255)\n`visitorteam_id` varchar(255)\nRun Code Online (Sandbox Code Playgroud)\n\n改进查询\xe2\x80\xa6
\n\n当我读到它时,您是matches_of_comments按最新评论订购的。您还需要评论数量,所以我们首先这样做。假设您要对前 10 个分页,查询将如下所示:
SELECT match_static_id,\n MAX( TIMESTAMP ) maxtimestamp,\n COUNT( match_static_id ) AS comments_no\nFROM comments\nGROUP BY match_static_id\nORDER BY maxtimestamp DESC\nLIMIT 10 OFFSET 0\nRun Code Online (Sandbox Code Playgroud)\n\n就这样。
\n\n如果您增加限制,它会为您提供更多 10 个 ID \xe2\x80\x94。在您的应用程序中循环遍历它们并构建一个in (\xe2\x80\xa6)子句,该子句将允许您根据需要从其他表中获取每个单独的数据位;您可以通过一个或多个查询来完成此操作,这没什么关系。重点是避免加入该聚合,以便索引可用于后续查询。
通过完全删除上述查询,您可以更显着地改进事情。
\n\n为此,请向 中添加三个字段matches_of_comments,即last_comment_timestamp、last_comment_user_id和num_comments。使用触发器维护它们,并在 上添加索引(flag, last_comment_timestamp)。这将允许您运行以下有效的查询:
SELECT matches_of_comments.static_id,\n matches_of_comments.num_comments,\n matches_of_comments.last_comment_timestamp,\n matches_of_comments.last_comment_user_id,\n matches_of_comments.localteam_name,\n matches_of_comments.visitorteam_name,\n matches_of_comments.localteam_goals, \n matches_of_comments.visitorteam_goals,\n matches_of_comments.match_status\nFROM matches_of_comments\nWHERE matches_of_comments.flag = 1\nORDER BY matches_of_comments.last_comment_timestamp DESC\nLIMIT 10 OFFSET 0\nRun Code Online (Sandbox Code Playgroud)\n\n然后,您只需使用带有子句的单独查询(如前所述)从 \ usersxe2 new_iddaa\x80\x94中选择所需的数据。in (\xe2\x80\xa6)