php:在XSLT中直接传递参数,而不是在数组中

Question

我遇到的问题是XSLT如何将参数传递给我的PHP函数.我<xsl:value-of select="php:function('form::validate_add',@name,type,message)" />用来将属性名称,元素类型和元素消息传递给php函数,但传递的参数是大数组,包括我需要的无用信息.

XML:

<element name='text2-1'>
    <type>required</type>
    <message>The field Enter Text is required</message>
</element>
<element name='textarea'>
    <type>required</type>
    <message>The textarea is required</message>
</element>

XSLT:

<xsl:for-each select="element">
   <xsl:value-of select="php:function('form::validate_add',@name,type,message)" />
</xsl:for-each>

PHP:

public static function validate_add($name, $type, $message=NULL) {
#tmp
print_r($name);
}

返回:

Array
(
    [0] => DOMAttr Object
        (
            [name] => name
            [specified] => 1
            [value] => text2-1
            [ownerElement] => (object value omitted)
            [schemaTypeInfo] => 
            [nodeName] => name
            [nodeValue] => text2-1
            [nodeType] => 2
            [parentNode] => (object value omitted)
            [childNodes] => (object value omitted)
            [firstChild] => (object value omitted)
            [lastChild] => (object value omitted)
            [previousSibling] => 
            [attributes] => 
            [ownerDocument] => (object value omitted)
            [namespaceURI] => 
            [prefix] => 
            [localName] => name
            [baseURI] => 
            [textContent] => text2-1
        )

)

所以看起来数组的"值"键是我追求的正确值.有没有办法直接传递这个参数而不是传递整个数组并且必须从PHP函数中的数组中提取正确的值？我宁愿不改变我的PHP功能或添加新功能.

Answer 1

如果要从XPath/XSLT传递DOM节点的字符串值,请使用 <xsl:value-of select="php:function('form::validate_add', string(@name), string(type), string(message))" />