如何从android中的联系人列表中删除重复的联系人

Question

请看一看 :-

 public static ArrayList<ContactsEntityBean> getContactDetails(
            Context mContext) {
        ArrayList<ContactsEntityBean> contactList = new ArrayList<ContactsEntityBean>();
        ContentResolver cr = mContext.getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur
                        .getColumnIndex(ContactsContract.Contacts._ID));
                Cursor cur1 = cr.query(
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                        null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                + " = ?", new String[] {
                            id
                        }, null);
                while (cur1.moveToNext()) {
                    ContactsEntityBean contactsEntityBean = new ContactsEntityBean();
                    // to get the contact names
                    String name = cur1
                            .getString(cur1
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

                    // Log.e("Name :", name);
                    String email = cur1
                            .getString(cur1
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                    // Log.e("Email", email);
                    contactsEntityBean.setName(name);
                    contactsEntityBean.setEmail(email);
                    if (email != null) {
                        contactList.add(contactsEntityBean);
                    }
                }
                cur1.close();
            }
        }
        return contactList;
    }

这个方法是从同一个用户返回多个联系人,假设我已经为同一个用户存储了abc @ gmail.com,abc @ gmail.com,所以它返回abc@gmail.com&abc@gmail.com但我只想要一个记录abc @ gmail.com

 public static ArrayList<SearchEntityBean> getContactEmailDetails(
            Context mContext) {
        ArrayList<SearchEntityBean> contactList = new ArrayList<SearchEntityBean>();


        try {
            ContentResolver cr = mContext.getContentResolver();
            Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                    null, null, null);
            if (cur.getCount() > 0) {
                while (cur.moveToNext()) {
                    String email = "";
                    String id = cur.getString(cur
                            .getColumnIndex(ContactsContract.Contacts._ID));

                    Cursor cur1 = cr.query(
                            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                            null,
                            ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                    + " = ?", new String[] {
                                id
                            }, null);
                    SearchEntityBean contactsEntityBean = new SearchEntityBean();
                    while (cur1.moveToNext()) {

                        // to get the contact names

                        String name = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                        String image = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_ID));
                        String mail = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                        if (mail != null) {
                            if (!mail.equalsIgnoreCase(LoginPreferenceClass
                                    .getEmailID(mContext)))
                                email = email + mail + ",";
                        }
                        // Log.e("rohit", "Contact  Email :" + email);
                        contactsEntityBean.setName(name);
                        contactsEntityBean.setImage(image);

                    }

                    if (email != null) {

                        if (email.length() > 0) {

                            if (email.split(",").length > 1) {

                                contactsEntityBean.setMutipleEmail(true);

                            }

                            contactsEntityBean.setUserType("2");
                            contactsEntityBean.setContactId(id);
                            contactsEntityBean.setEmail(email);
                            contactList.add(contactsEntityBean);
                        }
                    }
                    cur1.close();
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
        HashSet<SearchEntityBean> hs = new HashSet<SearchEntityBean>();
        hs.addAll(contactList);
        contactList.clear();
        contactList.addAll(hs);
        return contactList;
    }

Answer 1

你应该在ContactsEntityBean下面修改你的喜欢

public class ContactsEntityBean {
    private HashSet<String> emails = new HashSet<String>(); 

    public void setEmail(String email) {
        if (email == null)
            return; 
        this.emails.add(email.trim()); 
    }

    public HashSet<String> getEmails() {
        return this.emails; 
    }
}

会关心重复的电子邮件……您可以对地址、电话等使用相同的逻辑。

ContactsEntityBean用下面的代码替换你的

public class ContactsEntityBean {
    private HashSet<String> emails;
    private HashSet<String> phones;
    private HashSet<String> addresses;
    private String contactId;
    private boolean checked = false;

    public ContactsEntityBean() {
        this.emails = new HashSet<String>();
        this.phones = new HashSet<String>();
        this.addresses = new HashSet<String>();
    }

    public HashSet<String> getPhones() {
        return phones;
    }

    public void setPhones(String phone) {
        if (phone == null)
            return;
        this.phones.add(phone.trim());
    }

    public HashSet<String> getAddresses() {
        return addresses;
    }

    public void setAddresses(String address) {
        if (address == null)
            return;
        this.addresses.add(address.trim());
    }

    public void setEmails(String email) {
        if (email == null)
            return;
        this.emails.add(email.trim());
    }

    public HashSet<String> getEmails() {
        return emails;
    }

    public String getContactId() {
        return contactId;
    }

    public void setContactId(String contactId) {
        this.contactId = contactId;
    }

    public boolean isChecked() {
        return checked;
    }

    public void setChecked(boolean checked) {
        this.checked = checked;
    }
}

并且无需关心重复项。这会关心所有的事情..

Answer 2

这是我的工作

private void getContactDetails(ContentResolver contentResolver) {

        Cursor phones = contentResolver.query(
                ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null,
                null, null);
        HashSet<String> mobileNoSet = new HashSet<String>();

        while (phones.moveToNext()) {
            String name = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
            String phoneNumber = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            String email = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Email.ADDRESS));
            String imagUri = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Photo.PHOTO_URI));
            long id = phones.getColumnIndex(ContactsContract.Contacts._ID);

            if (!mobileNoSet.contains(phoneNumber)) {
                arrayContacts.add(new Contact(name, phoneNumber, email,
                        imagUri, id));
                mobileNoSet.add(phoneNumber);
            }
        }

        adapterContact = new AdapterContact(getActivity(), arrayContacts);
        listContact.setAdapter(adapterContact);
    }