sca*_*e13 22 javascript mobile json angularjs cordova
我正在尝试使用angular.js,hammer.js和topcoat来制作和移动webapp.
我在显示像这样的Json文件中的数据时遇到了一些麻烦:
{
"version": "1",
"artists": {
"artist1": {
"name": "artist1name",
"jpeg": "../img/artist/artist1.jpg",
"albums": {
"album1": {
"type": "cd",
"title": "titlealbum1",
"subtitle": "subtitlealbum1",
"jpeg": "../img/album1.jpg",
"price": "12.00",
"anystring1": "anystring1album1",
"anystring2": "anystring2album1"
},
"album2": [{
"type": "cd",
"title": "titlealbum2",
"subtitle": "subtitlealbum2",
"jpeg": "../img/album2.jpg",
"price": "12.00",
"anystring1": "anystring1album2",
"anystring2": "anystring2album2"
}],
"album3": [{
"type": "cd",
"title": "titlealbum3",
"subtitle": "subtitlealbum3",
"jpeg": "../img/album3.jpg",
"price": "13.00",
"anystring1": "anystring1album3",
"anystring2": "anystring2album3"
}]
}
},
"artist2": {
"name": "artist2name",
"jpeg": "../img/artist/artist2.jpg",
Run Code Online (Sandbox Code Playgroud)
我的js文件是这样的:
angular.module('list', [])
function ListCtrl ($scope, $http) {
$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data)
{
$scope.artists = data.artists; // response data
$scope.albums = data.artists.albums; /this is where im getting trouble
});
};
Run Code Online (Sandbox Code Playgroud)
我的HTML文件是这样的:
<body ng-app="list">
<h3>Titulos</h3>
<div ng-controller="ListCtrl">
<ul ng-repeat="artist in artists">
<li >{{artist.name}}</li>
</ul>
</div>
<div ng-controller="ListCtrl">
<ul ng-repeat="album in albums">
<li >{{album.title}}</li> //not working here.
</ul>
</div>
Run Code Online (Sandbox Code Playgroud)
我想显示所有相册,如果我的用户选择了特定的艺术家,我想过滤这些相册.这里的问题是如何在这个嵌套的json上选择.顺便说一句,artist.name正确显示.
第二个问题是,我将如何使用文本字段过滤这些艺术家.
Ada*_*dam 14
我建议像这样:
$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data) {
$scope.artists = [];
angular.forEach(data.artists, function(value, key) {
$scope.artists.push(value);
});
$scope.isVisible = function(name){
return true;// return false to hide this artist's albums
};
});
Run Code Online (Sandbox Code Playgroud)
然后:
<div ng-controller="ListCtrl">
<ul>
<li ng-repeat="artist in artists">{{artist.name}}</li>
</ul>
<ul ng-repeat="artist in artists" ng-show="isVisible(artist.name)">
<li ng-repeat="album in artist.albums">{{album.title}}</li>
</ul>
</div>
Run Code Online (Sandbox Code Playgroud)
您的所有问题都以您的JSON开头.我建议你简化你的JSON,让每个Artist和Album对象和Artists与Albums对象的数组.
试试这个:
{
"version": "1",
"artists": [
{
"name": "artist1name",
"jpeg": "../img/artist/artist1.jpg",
"albums": [
{
"type": "cd",
"title": "titlealbum1",
"subtitle": "subtitlealbum1",
"jpeg": "../img/album1.jpg",
"price": "12.00",
"anystring1": "anystring1album1",
"anystring2": "anystring2album1"
},
{
"type": "cd",
"title": "titlealbum2",
"subtitle": "subtitlealbum2",
"jpeg": "../img/album2.jpg",
"price": "12.00",
"anystring1": "anystring1album2",
"anystring2": "anystring2album2"
},
{
"type": "cd",
"title": "titlealbum3",
"subtitle": "subtitlealbum3",
"jpeg": "../img/album3.jpg",
"price": "13.00",
"anystring1": "anystring1album3",
"anystring2": "anystring2album3"
}
]
},
{
"name": "artist2name",
"jpeg": "../img/artist/artist2.jpg",
"albums": []
}
]
}
在我的示例中,数组可以为空(artist2没有分配相册).
您的错位也是错误的,在您ListCtrl知道正确之前,您无法分配和显示相册Artist.如果您想要显示所有艺术家的所有专辑,您需要遍历所有艺术家.
示例控制器:
angular.module('list', []);
function ListCtrl($scope, $http) {
$http({
method: 'GET',
url: 'json_price_1.json'
}).success(function(data) {
$scope.artists = data.artists; // response data
$scope.albums = [];
angular.forEach(data.artists, function(artist, index) {
angular.forEach(artist.albums, function(album, index){
$scope.albums.push(album);
});
});
});
}Run Code Online (Sandbox Code Playgroud)
这里是基于jessie示例修改的Plunkr:http://plnkr.co/edit/zkUqrPjlDYhVeNEZY1YR?p = preview
小智 5
检查柱塞链接
回答您的问题“我如何选择此嵌套json?”
$.each(data.artists, function(index, element){
$.each(this.albums, function(index, element){
$scope.albums.push(element);
});
});
Run Code Online (Sandbox Code Playgroud)
回答您的问题“我将如何用文本字段过滤那些艺术家?”
<input ng-model="searchText.artistName">
<ul ng-repeat="album in albums | filter:searchText">
<li>{{album.title}}</li>
</ul>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
68801 次 |
| 最近记录: |