3 formbuilder symfony fosuserbundle
我尝试从CategoryType表单设置字段"author"的值.我希望它是来自使用FOS包登录的当前用户的用户ID.
我的CategoryType表单:
namespace My\CategoryBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
class CategoryType extends AbstractType
{
private $userId;
public function __construct(array $userId)
{
$this->userId = $userId;
}
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('title')
->add('author')
->add('content')
;
}
/**
* @param OptionsResolverInterface $resolver
*/
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'My\CategoryBundle\Entity\Category',
'auteur' => $this->userId
));
}
/**
* @return string
*/
public function getName()
{
return 'my_categorybundle_category';
}
}
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而我的控制器动作:
public function addAction()
{
$category = new Category;
$user = $this->get('security.context')->getToken()->getUser();
$userId = $user->getId();
$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));
$request = $this->get('request');
if ($request->getMethod() == 'POST') {
$form->bind($request);
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($category);
$em->flush();
return $this->redirect($this->generateUrl('mycategory_voir',
array('id' => $category->getId())));
}
}
return $this->render('MyCategoryBundle:Category:add.html.twig',
array(
'form' => $form->createView(),
));
}
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我在运行动作时发现了这个错误:
可捕获致命错误:传递给My\CategoryBundle\Form\CategoryType :: __ construct()的参数1必须是数组,没有给定,在第55行的/My/CategoryBundle/Controller/CategoryController.php中调用,并在/ My/CategoryBundle中定义/Form/CategoryType.php第13行
它不是已经传递给表单的数组吗?
Pet*_*ley 10
你的问题就在这条线上
$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));
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你不满意合同My\CategoryBundle\FormCategoryType::__construct().在这里,让我们以另一种方式看待它.
$form = $this->get('form.factory')->create(
new CategoryType(/* You told PHP to expect an array here */)
, array('author' => $userId)
);
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作为第二个参数发送的数组Symfony\Component\Form\FormFactory::create()是最终作为$options数组注入的数组My\CategoryBundle\Form\CategoryType::buildForm()
在我看来,你有几种不同的方法可以解决这个问题
更新参数签名并调用My\CategoryBundle\FormCategoryType::__construct()以传递/接收整个用户对象(而不仅仅是他们的id - 请记住此时您正在使用Doctrine关系,而不是他们映射到的低级外键)
namespace My\CategoryBundle\Form;
use My\CategoryBundle\Entity\User; /* Or whatver your User class is */
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
class CategoryType extends AbstractType
{
private $author;
public function __construct( User $author )
{
$this->author = $author;
}
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和
$form = $this->get('form.factory')->create(
new CategoryType(
$this->get('security.context')->getToken()->getUser()
)
);
Run Code Online (Sandbox Code Playgroud)不要将User类型注入到类型的构造函数中,只需让选项处理它
namespace My\CategoryBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
class CategoryType extends AbstractType
{
private $userId;
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('title')
->add('author', 'hidden', array('data'=>$options['author']))
->add('content')
;
}
/**
* @param OptionsResolverInterface $resolver
*/
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'My\CategoryBundle\Entity\Category'
));
}
/**
* @return string
*/
public function getName()
{
return 'my_categorybundle_category';
}
}
Run Code Online (Sandbox Code Playgroud)甚至不打扰将作者放在表单中并让控制器处理它
$form = $this->get('form.factory')->create(
new CategoryType()
, array('author' => $this->get('security.context')->getToken()->getUser() )
);
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和
if ($request->getMethod() == 'POST') {
$form->bind($request);
if ($form->isValid()) {
$category->setAuthor(
$this->get('security.context')->getToken()->getUser()
);
$em = $this->getDoctrine()->getManager();
$em->persist($category);
$em->flush();
return $this->redirect($this->generateUrl('mycategory_voir',
array('id' => $category->getId())));
}
}
Run Code Online (Sandbox Code Playgroud)将表单类型转换为服务,并使用DI容器注入安全上下文
应用程序/配置/ config.yml
services:
form.type.my_categorybundle_category:
class: My\CategoryBundle\Form\CategoryType
tags:
- {name: form.type, alias: my_categorybundle_category}
arguments: ["%security.context%"]
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更新您的类型以接收安全上下文
namespace My\CategoryBundle\Form;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
class CategoryType extends AbstractType
{
private $author;
public function __construct( SecurityContext $security )
{
$this->author = $security->getToken()->getUser();
}
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然后在您的控制器中,使用其服务名称创建表单
$form = $this->get('form.factory')->create('my_categorybundle_category');
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