SQL DELETE与JOIN另一个表用于WHERE条件

hsz*_*hsz 70 mysql sql delete-row mysql-error-1093 sql-delete

我必须删除guide_categoryguidetable 无关的行(死关系).

这是我想要做的,但它当然不起作用.

DELETE FROM guide_category AS pgc 
 WHERE pgc.id_guide_category IN (SELECT id_guide_category 
                                   FROM guide_category AS gc
                              LEFT JOIN guide AS g ON g.id_guide = gc.id_guide
                                  WHERE g.title IS NULL)
Run Code Online (Sandbox Code Playgroud)

错误:

您不能在FROM子句中为更新指定目标表'guide_category'

Qua*_*noi 106

由于锁定实现问题,MySQL不允许使用DELETE或引用受影响的表UPDATE.

你需要在JOIN这里做一个:

DELETE  gc.*
FROM    guide_category AS gc 
LEFT JOIN
        guide AS g 
ON      g.id_guide = gc.id_guide
WHERE   g.title IS NULL
Run Code Online (Sandbox Code Playgroud)

或者只是使用NOT IN:

DELETE  
FROM    guide_category AS gc 
WHERE   id_guide NOT IN
        (
        SELECT  id_guide
        FROM    guide
        )
Run Code Online (Sandbox Code Playgroud)

  • 如果您使用的是TSQL,请使用`DELETE gc`而不是`DELETE gc.*` (14认同)
  • 对于MySQL> 5.0,它也是`DELETE gc`而不是`gc.*` (4认同)

Dir*_*irk 9

我认为,根据您的描述,以下内容就足够了:

DELETE FROM guide_category 
WHERE id_guide NOT IN (SELECT id_guide FROM guide)
Run Code Online (Sandbox Code Playgroud)

我假设,所涉及的表没有参照完整性约束,是吗?


小智 5

尝试这个示例 SQL 脚本以便于理解,

CREATE TABLE TABLE1 (REFNO VARCHAR(10))
CREATE TABLE TABLE2 (REFNO VARCHAR(10))

--TRUNCATE TABLE TABLE1
--TRUNCATE TABLE TABLE2

INSERT INTO TABLE1 SELECT 'TEST_NAME'
INSERT INTO TABLE1 SELECT 'KUMAR'
INSERT INTO TABLE1 SELECT 'SIVA'
INSERT INTO TABLE1 SELECT 'SUSHANT'

INSERT INTO TABLE2 SELECT 'KUMAR'
INSERT INTO TABLE2 SELECT 'SIVA'
INSERT INTO TABLE2 SELECT 'SUSHANT'

SELECT * FROM TABLE1
SELECT * FROM TABLE2

DELETE T1 FROM TABLE1 T1 JOIN TABLE2 T2 ON T1.REFNO = T2.REFNO
Run Code Online (Sandbox Code Playgroud)

您的情况是:

   DELETE pgc
     FROM guide_category pgc 
LEFT JOIN guide g
       ON g.id_guide = gc.id_guide 
    WHERE g.id_guide IS NULL
Run Code Online (Sandbox Code Playgroud)