-3 php validation
好吧,我想要实现的是一个非常简单的表单验证,如下所示.
但是,一旦我单击提交(如果字段为空或填充),我将在空白页面上显示所有回显的错误.
"名称必须至少为2个字符名称为requiredemail必须至少3个字符无效,电子邮件不能留空"
我的代码到目前为止:
的index.php
<form method="post" action="confirm.php">
Name:<input type="text" name="name" />
email:<input type="text" name="email" />
DOB:<input type="date" name="dob" />
<input type="submit" value="submit" />
</form>
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和
confirm.php
<?php
$name = $_POST['$name'];
$email = $_POST['$email'];
$dob = $_POST['$dob'];
$namelen = strlen($email);
$emaillen = strlen($email);
$max = 255;
$minname = 2;
$minemail = 3;
if($namelen<$minname){
echo"name must be at least 2 characters";
}
elseif($namelen>$max){
echo"name must be less than 255 characters";
}
if(empty($name)){
echo"name is required";
}
else{
continue;
}
if($emaillen<$minemail){
echo"email must be at least 3 characters";
}
elseif($emaillen>$max){
echo"email must be less than 255 characters";
}
if(filter_var($email, FILTER_VALIDATE_EMAIL)){
continue;
}
else{
echo"invalid email";
}
if(empty($email)){
echo"email cannot be left empty";
}
else{
continue;
}
?>
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非常感谢帮助,谢谢.
alert是一个JavaScript函数,而不是PHP函数.如果要在PHP中使用警报功能,则需要创建一个自定义的函数,如下所示:
function alert($alertMessage){
//Do something with $alertMessage
}
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错误:
致命错误:调用未定义的函数alert()
基本上意味着PHP无法找到一个名为alert的函数.