XCTAssertEqual:如何比较NSDates？

Question

NSDate *date = [NSDate date];
XCTAssertEqual([[store selectedDate] timeIntervalSinceReferenceDate], [date timeIntervalSinceReferenceDate]);

这给了我错误信息:

(([[store selectedDate] timeIntervalSinceReferenceDate]) equal to ([date timeIntervalSinceReferenceDate])) failed: 
("405290648.294") is not equal to ("405290648.294")

我以前遇到过与Integers类似的问题,必须通过将其转换NSUInteger为此处所述来解决.

但我无法弄清楚如何使用NSDate对象/双精度解决这个问题(如本例所示).

Answer 1

用于XCTAssertEqualWithAccuracy比较浮点数

XCTAssertEqualWithAccuracy([[store selectedDate] timeIntervalSinceReferenceDate], [date timeIntervalSinceReferenceDate], 0.001);

Answer 2

在早期的 Swift 中你需要使用这个：

let receivedDateTimeInterval = receivedDate.timeIntervalSinceReferenceDate
let expectedDateTimeInterval = expectedDate.timeIntervalSinceReferenceDate
XCTAssertEqualWithAccuracy(receivedDateTimeInterval, expectedDateTimeInterval, accuracy: 0.001)

现在你可以失去“WithAccuracy”部分：

XCTAssertEqual(receivedDateTimeInterval, expectedDateTimeInterval, accuracy: 0.001)